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ElenaW [278]
3 years ago
12

What is the surface area of the cylinder with height 8 in and radius 2 in? Round your answer to the nearest thousandth.

Mathematics
1 answer:
leonid [27]3 years ago
6 0

Answer:

2^2 = 4

4 x 3.14 = 12.56

12.56 x 2 (since there are two circles on the cylinder) = 25.12

Now let's find the circumference of one circle and multiply it by the height to get the round surface area!

2 x 3.14 x 2 = 12.56(circumference)

12.56 x 8(height) = 100.48

Now add both the surface areas!:

25.12 + 100.48 = 125.6 in2 is your answer.

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There are 42 students on a large bus and the rest are on a smaller bus. If 40% of the students are on the smaller bus how many t
Liono4ka [1.6K]

Answer:

<u>There are 70 students on the two buses, 42 on the large and 28 on the smaller.</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Number of students on the large bus = 42

Number of students on the small bus = 40% of the students

2. How many total students are on the two buses?

For answering the question, we will use the Rule of Three Simple, this way:

42 students are 60% of total students, how much students are the 100%?

Total students = 42 * 100/60

Total students = 4,200/60 = 70

<u>There are 70 students on the two buses, 42 on the large and 28 on the smaller.</u>

5 0
3 years ago
R+b=7 <br> 3.75r+2.75b=22.25
stiv31 [10]

Answer:

Step-by-step explanation:

hello :

r+b=7... (*)

3.75r+2.75b=22.25.... (**)

use (*) :  r = 7 - b

put this value in (**) :

3.75(7 - b)+2.75b =  22.25

26.25 -375b +2.75b = 22.5

-375b +2.75b = 22.5 - 26.25

- b = -3.75

so : b  = 3.75

but : r = 7 - b

r = 7 - 3.75

r = 3.25

6 0
3 years ago
Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.950.950, point, 95 pro
bearhunter [10]

The question is incomplete. Here is the complete question:

Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.95 probability that he will hit it. One day, Samir decides to attempt to hit  10 such targets in a row.

Assuming that Samir is equally likely to hit each of the 10 targets, what is the probability that he will miss at least one of them?

Answer:

40.13%

Step-by-step explanation:

Let 'A' be the event of not missing a target in 10 attempts.

Therefore, the complement of event 'A' is \overline A=\textrm{Missing a target at least once}

Now, Samir is equally likely to hit each of the 10 targets. Therefore, probability of hitting each target each time is same and equal to 0.95.

Now, P(A)=0.95^{10}=0.5987

We know that the sum of probability of an event and its complement is 1.

So, P(A)+P(\overline A)=1\\\\P(\overline A)=1-P(A)\\\\P(\overline A)=1-0.5987\\\\P(\overline A)=0.4013=40.13\%

Therefore, the probability of missing a target at least once in 10 attempts is 40.13%.

6 0
3 years ago
Read 2 more answers
Which diagram shows lines that must be parallel lines cut by a transversal? 2 horizontal lines are intersected by a third line.
ivanzaharov [21]

Answer:

  (A)  At the intersection of the first line with the third line, the bottom left angle is 115 degrees. At the intersection of the second line with the third line, the uppercase left angle is 65 degrees.

Step-by-step explanation:

Alternate interior angles are supplementary when parallel lines are crossed by a transversal. The first description seems to be describing alternate interior angles. (See attachment)

_____

<em>Comment on orientation</em>

If the transversal is oriented horizontally, then the descriptions of the angles will be of different angles than assumed here.

8 0
3 years ago
Read 2 more answers
Solve for x 6-12x = -54
kvasek [131]

Answer:

The answer of the question is 5

8 0
3 years ago
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