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goldfiish [28.3K]
3 years ago
13

A trapezoid has an altitude of 12 cm. Its parallel sides measure 10 and 8 cm, respectively. What is its area?

Mathematics
2 answers:
Maurinko [17]3 years ago
8 0
108cm^2 is the answer hope this helps!
stira [4]3 years ago
4 0
Area of trapezoid = 1/2(b1+b2)(h) 
<span>1/2(10 cm + 8 cm)(12cm) = </span>

<span>108 cm^2</span>
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Enter product in simplest form<br>1/4×7 4/5​
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Answer:

i believe the answer is 39/20 which could also be 13/7

Step-by-step explanation:

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What is the answer for I=E/R for E
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http://lianmath.com/describe-a-serie-of-shifts-that-translates-the-graph-yx-93-4-back-onto-the-graph-of-yx-3/


7 0
3 years ago
If possible may someone help me please?
Orlov [11]

Answer:

Given, ∠MNP=107 degree.

Therefore, ∠QPN= 107 degree. [as, MN=PQ]

We know, sum of four angles of a quadrilateral is 360 degree.

And as MN=PQ, ∠NMQ=∠MQP.

Therefore, ∠MQP= {360 degree-( 107degree+ 107 degree)}/2

                             =( 360 degree-214 degree)/2

                            = 146 degree/2

                            =73 degree.

hope this will help you.

                           

Step-by-step explanation:

4 0
3 years ago
How do i solve this?
ss7ja [257]

Answer:

O

Step-by-step explanation:

8 0
3 years ago
How to solve this problem​
nevsk [136]

Let C be the center of the circle. The measure of arc VSU is 2+114x, so the measure of the minor arc VU is 360-(2+114x)=358-114x. The central angle VCU also has measure 358-114x.

Triangle CUV is isosceles, so the angles CVU and CUV are congruent. The interior angles of any triangle are supplementary (they add to 180 degrees) so

m\angle VCU+2m\angle CUV=180

\implies m\angle CUV=\dfrac{180-(358-114x)}2=57x-89

UT is tangent to the circle, so CU is perpendicular to UT. Angles CUV and VUT are complementary, so

(57x-89)+(31x+3)=90

\implies88x=176

\implies x=2

So finally,

m\widehat{VSU}=2+114\cdot2=230

degrees.

6 0
3 years ago
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