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Olegator [25]
3 years ago
6

johns test grades in his science class are 82, 93, 75, and 89 what is his average? 1. (87.45) 2. (80.00) 3. (90.40) 4. (89.25) 5

. (84.75)
Mathematics
2 answers:
Natali5045456 [20]3 years ago
8 0

Answer:

The average of the John scores is 84.75.

Step-by-step explanation:

Formula of average is given as :

A=\frac{\text{Sum of all the terms}}{\text{Number of terms}}

We have:

Test grades of John: 82, 93, 75, and 89

Number of terms - 4

Average of the score of the John;

a=\frac{82 + 93 +75 + 89}{4}=84.75

The average of the John scores is 84.75.

inessss [21]3 years ago
5 0

First you add all the numbers together. So you add 82+93+75+89 to get 339. Once you get that, you divide it by the amount of numbers there are. In this case, it's 4. 339 divided by 4 is 84.75.

HOPE THIS HELPS!!

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Part A:

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-3 - (-11) = -3 + 11 = 8.

Thus, the value of the output increases by 8 units for each one unit increase in the input.



Part B:

Consider from x = -3 to x = -1, they are 2 units apart and the difference of their outputs is given by:

21 - 5 = 16.

Thus, the value of the output increases by 16 units for each two units increase in the input.



Part C:

Consider from x = 0 to x = 3, they are 3 units apart and the difference of their outputs is given by:

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Thus, the value of the output increases by 24 units for each three units increase in the input.



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from the edge of a cliff 180m high, the angles of depression of two boats at sea are 43° and 52° respectively what is the distan
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| 9. The distance between Town A and Town B was 108 km. A car and a van left Town A at 12 00 for Town B. On reaching Town B, the
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Answer:

a)  Time until both vehicles meet is 1.5 hours after starting at noon.  That makes it 1:30PM.

b)  Average speed of car is 84 km/h

Step-by-step explanation:

A -----------------------z------------B

          <u>Left</u>      <u>Speed(km/h)</u>      <u>Time</u>

Car:   12PM            X  

Van:   12PM           60

Car/Van

DistanceCar        AB + z

DistanceVan       Az

Ratio:                  (AB+z)/Az  = 7/5

Time until both meet = T (in hours)

Distance Car:            xT

Distance Van:           60T

====

  xT = AB + z

  60T = Az

---

(xT/60T)= (7/5)

x = 60(7/5)

x = 84 km/h

=====

Time for car to reach B is:    time (hr) = 108 km/(84 km/h)

                                                 time = 1.286 hours

Distance for at 1.289 hours is:    distance (km) = (60 km/h)*(1.286 h)

                                                   distance = 77.14 km

At 1.286 hours, the car reverses direction.  The van is (108 km - 77.14 km) or 30.86 km away.

Add the distances travelled by both vehicles after the car reverses direction at 1.286 hours.  The sum will be 30.86 km when they meet, at time of T.

Car Distance + Van Distance = 30.86 km

T(84 km/h) + t(60 km)

They meet when they are 0 km apart, which can be modeled with the following equation:

Van travel Distance - Car Travel Distance = 0 starting at 1.286 hr.

Let <u>t</u> be the time <u>after</u> 1.286 hours that both vehicles meet/collide.

t*(60 km/h)  +  t(84 km/h) = 30.86 km

t(60+84) = 30.86 km

t(144 km/h) = 30.86 km

t = 0.2143 hr

Total time until the car and van meet is 1.286 hr + 0.2143 hr for a total of 1.50 hours.

=================

a)  Time until both vehicles meet is 1.5 hours after starting at noon.  That makes it 1:30PM.

b)  Average speed of car is 84 km/h

==============

<u>CHECK</u>

Is the ratio of the distance travelled by the car and the van until they meet in the ratio of 7/5?

Car distance is (1.5 hr)(84 km/h) = 126 km

Van distance is (1.5 hr)(60 km/h) = 90.0 km

Ratio is 126/90 or 1.4

Ratio of 7/5 is 1.4

<u><em>YES</em></u>

     

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