Answer:x=9
Step-by-step explanation:
To find the positive solution for this, then we will say;
Let the number be x
3x<x^2-54
x^2-3x-54<0
Then we are going to factorise
x^2-9x+6x-54=0
(x^2-9x)+(6x-54)=0
x(x-9)+6(x-9)=0
(x+6)(x-9)=0
Therefore, The positive solution for this is: x=9
Answer:
11.99
Step-by-step explanation:
First Chart: Perimeter
Square Portion:
Original Side Lengths: P = 4 (1 + 1 + 1 + 1 ) =4
Double Side Lengths: P = 8 (2 x 4 = 8)
Triple Side Lengths: P = 12 (4 x 3 = 12)
Quadruple Side Lengths: P = 16 (4 x 4 = 16)
Rectangle Portion:
Original Side Lengths: P = 6 (1 x 2 + 2 x 2 = 6)
Double Side Lengths: P = 12 (2 x 2 + 4 x 2 = 12)
Triple Side Lengths: P = 24 (4 x 2 + 8 x 2 = 24)
Quadruple Side Lengths: P = 48 (8 x 2 + 16 x 2 = 48)
Second Chart: Area
Square Portion:
Original Side Lengths: A = 1 (1 x 1 = 1)
Double Side Lengths: A = 4 (2 x 2 = 4)
Triple Side Lengths: A = 9 (3 x 3 = 9
Quadruple Side Lengths: A = 16 ( 4 x 4 = 16)
Rectangle Portion:
Original Side Lengths: A = 2 ( 1 x 2 = 2 )
Double Side Lengths: A = 8 ( 2 x 4 = 8)
Triple Side Lengths: A = 18 ( 3 x 6 = 18)
Quadruple Side Lengths: A = 32 (4 x 8 = 32)
P=2(L+W) and P=34 so
2(L+W)=34
L+W=17 so we can say
L=17-W
A=LW using L from above
A=(17-W)W
A=17W-W^2 and A=30 so
30=17W-W^2
W^2-17W+30=0
W^2-2W-15W+30=0
W(W-2)-15(W-2)=0
(W-15)(W-2)=0
So the dimensions of the rectangle are 15 meters by 2 meters.
3x - 3 = x +5
3x = 2
x = 2/3