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3 years ago

11

ALGEBRA 1 HELP URGENT!!

1 answer:

Lelechka [254]3 years ago

8 0

I would tell you but the answer wont show sorry. :)

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-4(9z -2)<br> hurrryyyyyyyyyyyyyyyyyyyyyyy

Sergio039 [100]

We will use the distributive property. -4 times 9z=-36z -4 times -2=8 so we have -36z+8 as our answer

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3 years ago

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16x - 15 - 9x = 13 how do you do this thank you

lisov135 [29]

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3 years ago

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Which products are negative?

Aliun [14]

Both A and D are negative products.

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2 years ago

Which of the following is equal to the expression above

EleoNora [17]

Answer:

$15 \sqrt[3]{2}$

Step-by-step explanation:

${(27 \times 250)}^{ \frac{1}{3} } = {(27 \times 125 \times 2)}^{ \frac{1}{3} } \\ = {27}^{ \frac{1}{3} } \times {125}^{ \frac{1}{3} } \times {2}^{ \frac{1}{3} } \\ = \sqrt[ 3]{27} \times \sqrt[3]{125} \times \sqrt[3]{2} \\ = \sqrt[3]{ {3}^{3} } \times \sqrt[3]{ {5}^{3} } \times \sqrt[3]{2} \\ = 3 \times 5 \times \sqrt[3]{2} \\ = 15 \sqrt[3]{2}$

4 0

3 years ago

Type the correct answer in the box. Round your answer to the nearest integer.

umka21 [38]

Answer:

m∠ADC = 132°

Step-by-step explanation:

From the figure attached,

By applying sine rule in ΔABD,

$\frac{\text{sin}(\angle ABD)}{\text{AD}}=\frac{\text{sin}(\angle ADB)}{AB}$

$\frac{\text{sin}(120)}{35}=\frac{\text{sin}(\angle ADB)}{30}$

sin(∠ADB) = $\frac{30\text{sin}(120)}{35}$

= 0.74231

m∠ADB = $\text{sin}^{-1}(0.74231)$

= 47.92°

≈ 48°

m∠ADC + m∠ADB = 180° [Linear pair of angles]

m∠ADC + 48° = 180°

m∠ADC = 180° - 48°

m∠ADC = 132°

4 0

3 years ago