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zhenek [66]
3 years ago
11

ALGEBRA 1 HELP URGENT!!

Mathematics
1 answer:
Lelechka [254]3 years ago
8 0
I would tell you but the answer wont show sorry. :)
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Jim spent 3/8 of his money on eggs. he spent 2/5 of the rest of his money on butter. he had $6.72 left. how much money did him s
anastassius [24]
First make the denominator equal for both fractions.
The LCM of 8 and 5 is 40, so 40 will be the common denominator.
3/8=15/40 and 2/5=16/40
Add them together.
15/40+16/40=31/40
He has 9/40 of his money left, which means 9/40 of the total money=$6.72
Make an equation to solve for how much money he had when he started (x).
6.72/x=9/40
After solving, x= about $29.87
3 0
2 years ago
Write both equations of the following system in the slope intercept form in order to decide how many solutions the system will h
anastassius [24]
Hi :) You don't need to get their slope-intercept form to know how many solutions this linear system has. Since there are two variable and 2 independent equations, there would be two solutions. One value each for the x and y variables. 

The answer is B.
5 0
3 years ago
M+2<br> ——— = 1<br> 10 <br> Need help <br> Show work
True [87]

Answer:answer is 8

m+2

——— = 1

10

m+2=10

m=10-2=8

8 0
3 years ago
Can someone explain this to me? ​
Brilliant_brown [7]

Answer:

y=42 degrees.

Step-by-step explanation:

The sum of angles in a triangle = 180 degrees.

One angle in that small triangle is y, one is 48, and one is unknown.

The sum of angles on one line is 180 degrees.

One of the angles on the line that unknown angle lies on is 90 degrees, so the unknown angle is 90 degrees, too.

90 + 48 = 138

180 - 138 = 42.

4 0
3 years ago
URGENT PLEASE ANSWER THESE
Alex787 [66]

The distance of the cruise liner from me 20 seconds later will be; 2600ft.

<h3>How far will the cruise liner be in 20 seconds?</h3>

a) Since, the speed of the liner is 30ft/sec, it follows that after 20secs, the liner would cover; (30×20)ft = 600ft more; and consequently, the distance is now; √(2000²+600²) = ft.

b) For the boat to be 2500 ft away given the speed 30ft per sec; Time taken = 2500/30 = 83.3seconds. Hence, the boat will be more than 2500 feets away after 2 minutes.

c) If the boat's distance is 2000ft from me; it follows that the distance covered is 10 seconds is; √(2000²-1500²) = 1322.9ft

Hence, the speed to attain this distance is; 1322.9/10 = 132.29ft/sec.

Read more on speed;

brainly.com/question/6504879

#SPJ1

4 0
1 year ago
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