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3 years ago

Find the distance between 3,4 and 3,9

Mathematics

1 answer:

katen-ka-za [31]3 years ago

6 0

Answer:

The answer is 5.

Step-by-step explanation:

The distance formula is ↷

$d\sqrt{(x_2 - x_1)^{2}+ (y_2 - y_1)^{2} }$

All we got to to do right now is plug in!

$d = \sqrt{(x_2 - x_1)^{2}+ (y_2 - y_1)^{2} } \\ d = \sqrt{(3 - 3)^{2} + (9 - 4)^{2} } \\ d = \sqrt{(0)^{2} + (5)^{2} } \\ d = \sqrt{0 + 25} \\ d = \sqrt{25} \\ d = \sqrt{5}$

Therefore, the distance between 3,4 and 3,9 is 5.

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<h3>What is an expression?</h3>

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication and division.

The complete question is:

Suppose a radioactive sample initially contains N0unstable nuclei. These nuclei will decay into stable nuclei, and as they do, the number of unstable nuclei that remain, N(t), will decrease with time. Although there is no way for us to predict exactly when any one nucleus will decay, we can write down an expression for the total number of unstable nuclei that remain after a time t:

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where λ is known as the decay constant. Note that at t=0, N(t)=No, the original number of unstable nuclei. N(t) decreases exponentially with time, and as t approaches infinity, the number of unstable nuclei that remain approaches zero.

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Express your answer in terms of N0 and/or λ.

1) Equation given:

← I used α instead of λ just for editing facility..

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So, replace in the given equation:

$N9t) = Ne^{-\lambda t}$