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puteri [66]
3 years ago
9

A line the contains the point (-3,6) and (5,10)

Mathematics
1 answer:
wlad13 [49]3 years ago
5 0
Ok so for slope it's difference in y dividing by the difference of x. The difference of y is 10 - 6 which is 4, and the change in x is 5 - (-3) which is 8. Dividing 4 by 8 gets us 1/2. So the slope is 1/2. Slope intercept form would be y = mx + b, and the slope is 1/2 so it'd be y = (1/2)x + b. Plug in a point and you get b = 15/2. So the final slope intercept form would be y = (1/2)x + 15/2. For point slope form just put in a point and slope and you get y - 6 = (1/2) × (x + 3). Standard form would have to be arranged from slope intercept. So multiplying 2 to the slope intercept form we get 2y = x + 15. Subtracting x we get -x + 2y = 15. In standard form we don't want x to be negative so just multiply by negative one and we get x - 2y = -15.

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weeeeeb [17]

Let us draw a picture to make the things more clear.

Attached is the image.

We have been given that

\angle acd = 60 ^{\circ}

Therefore, we have

\angle dcb =90- 60= 30 ^{\circ}

Now, in triangle bcd, we have

\tan30 = \frac{5}{cd}\\
\\
\frac{1}{\sqrt 3}=\frac{5}{cd}\\
\\
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tan 60 = \frac{ad}{5\sqrt3} \\
\\
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\\
ad= 5\sqrt3 \times \sqrt 3\\
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Thus, ad is 15 cm.


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