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Furkat [3]
3 years ago
12

Jordan is running 5 miles for cross-country practice (track). She ran the first 2 miles in 12.5 minutes. How long will it take h

er to run all 5 miles at this speed?
Mathematics
1 answer:
pochemuha3 years ago
6 0

Answer:

31.25 minutes

Step-by-step explanation:

12.5 minutes divided by 2 (miles) = 1 mile per 6.25 minutes

6.25 x 5 = 31.25

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The product of (n2 – 6n + 3) and -4n is ? When this product is multiplied by -n, the result is ?
madreJ [45]

the result should be n5.

6 0
3 years ago
Divide. 15÷−5 Drag and drop the correct number into the box to complete the sentence. The quotient is Response area.
german

Answer:

15÷-5=-3

Step-by-step explanation:

8 0
3 years ago
Will mark as Brainliest...
tatiyna

Answer:

280 ft squared

Step-by-step explanation:

To find the area of the nonshaded portion, we can find the area of the entire floor and then subtract the shaded area.

The total area is that of a rectangle: 30 * 15 = 450 ft squared.

Now, the shaded region is made up of a rectangle and a triangle.

- The rectangle has length 8 and width 10, so its area is 10 * 8 = 80 ft squared.

- The triangle has base 12 and height 15, so using the area of a triangle formula: A=(bh)/2 (where b is the base and h is the height) = (12 * 15)/2 = 180/2 = 90 ft squared.

- The total shaded region is: 80 + 90 = 170 ft squared

Subtract 110 from 450: 450 - 170 = 280 ft squared.

Thus, the answer is 280 ft squared.

Hope this helps!

8 0
3 years ago
Read 2 more answers
If (x+3)÷ 3 = 9 what is x
Sveta_85 [38]

Answer:

x = 24

Step-by-step explanation:

9*3 = 27

27 - 3 = 24

x = 24

7 0
3 years ago
Read 2 more answers
I really am bad with math and just have given up
Slav-nsk [51]
Well hmmm does the graph open upwards or downwards?  well
is a quadratic, if the leading term's coefficient is negative, Down, if positive, Up

a)
now, let's see the leading term, -x², what's its coefficient? is -1 * x² or -1x², is -1, so is negative, thus is opening downwards

c)
x-intercepts occur, when y = 0, namely y = -x²-4x-3, so setting y to 0
0 = -x² -4x -3 take a common factor of -1, thus

0 = -1 (x²+4x+3)  <--- now, if we factor that out, notice, surely you've done many of these by now, so we end up with 

\bf \begin{array}{lcclll}&#10;0=x^2&+4x&+3\\&#10;&\uparrow &\uparrow \\&#10;&3+1&3\cdot 1&#10;\end{array}\\\\&#10;-----------------------------\\\\&#10;0=(x+3)(x+1)\implies &#10;\begin{cases}&#10;0=x+3\implies &-3=x\\&#10;0=x+1\implies &-1=x&#10;\end{cases}

so, the x-intercepts are at -3 and -1

d)

now, the y-intercepts, just set x = 0
y = -x²-4x-3, settting x to 0 y = -0²-4(0)-3, which is y = -3

so the sole y-intercept is at y = -3


now, let's get on to b)

b)   \bf \textit{vertex of a parabola}\\\\&#10;&#10;\begin{array}{lccclll}&#10;f(x)=&-1x^2&-4x&-3\\&#10;&\uparrow &\uparrow &\uparrow \\&#10;&a&b&c&#10;\end{array}\qquad &#10;\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad  {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)

and those are the coordinates, notice a = -1, b = -4 and c = -3

now, for

e)

well, all you have to do is, once you have the vertex, pick an x-value on the left-hand-side of the vertex, get they value for "y", or OUTPUT,

then pick another x-value, on the right-hand-side of the vertex, get the "y" value again, and plot away
7 0
3 years ago
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