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allochka39001 [22]
2 years ago
15

Complete the square for the equation 3x2 - 5x = 2

Mathematics
2 answers:
zepelin [54]2 years ago
4 0

3

2

−

5

=

2

3x^{2}-5x=2

3x2−5x=2

Factor

1

Move terms to the left side

3

2

−

5

=

2

3x^{2}-5x=2

3x2−5x=2

3

2

−

5

−

2

=

0

3x^{2}-5x-2=0

3x2−5x−2=0

2

Use the sum-product pattern

3

2

−

5

−

2

=

0

3x^{2}{\color{#c92786}{-5x}}-2=0

3x2−5x−2=0

3

2

+

−

6

−

2

=

0

3x^{2}+{\color{#c92786}{x}}{\color{#c92786}{-6x}}-2=0

3x2+x−6x−2=0

3

Common factor from the two pairs

(

3

2

+

)

+

(

−

6

−

2

)

=

0

(3x^{2}+x)+(-6x-2)=0

(3x2+x)+(−6x−2)=0

(

3

+

1

)

−

2

(

3

+

1

)

=

0

RSB [31]2 years ago
4 0

Answer:

4/5

Step-by-step explanation:

See image below:)

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An elephant at the zoo lost 32 pounds over 8 months. The elephant lost the same amount of weight each month. Enter an integer th
inna [77]

Answer:

<em> He would loose 4lbs.  a Month 32/8=4</em>

Step-by-step explanation:

<em>First thing you need to do is to get the months down to one. so you need to divide 32/8 to get the pounds per month</em>

3 0
3 years ago
Read 2 more answers
What is the surface area of the figure?
Oliga [24]

Answer:

The total surface area = 582 ft²

Step-by-step explanation:

To find the surface area of it count the number of faces at first

The figure has 8 faces each 2 are equal

1- Two faces with dimensions 4 ft and 15 ft ( base and shaded face)

2- Two faces with dimensions 9 ft and 4 ft

3- Two faces with dimensions 4 ft and 6 ft

4- Two faces with dimensions 15 ft , 9 ft and 6 ft

Area of (1-) = 2(4 × 15) = 120 ft²

Area of (2-) = 2(4 × 9) = 72 ft²

Area of (3-) = 2(4 × 6) = 48 ft²

Area of (4-) = 2[(9 × 9) + (6 × 15)] = 2[81 + 90] = 2 × 171 = 342 ft²

∴ The total surface area = 120 + 72 + 48 + 342 = 582 ft²

5 0
3 years ago
Find the derivative of the function f(x) = (x3 - 2x + 1)(x – 3) using the product rule.
julsineya [31]

Answer:

Step-by-step explanation:

Hello, first, let's use the product rule.

Derivative of uv is u'v + u v', so it gives:

f(x)=(x^3-2x+1)(x-3)=u(x) \cdot v(x)\\\\f'(x)=u'(x)v(x)+u(x)v'(x)\\\\ \text{ **** } u(x)=x^3-2x+1 \ \ \ so \ \ \ u'(x)=3x^2-2\\\\\text{ **** } v(x)=x-3 \ \ \ so \ \ \ v'(x)=1\\\\f'(x)=(3x^2-2)(x-3)+(x^3-2x+1)(1)\\\\f'(x)=3x^3-9x^2-2x+6 + x^3-2x+1\\\\\boxed{f'(x)=4x^3-9x^2-4x+7}

Now, we distribute the expression of f(x) and find the derivative afterwards.

f(x)=(x^3-2x+1)(x-3)\\\\=x^4-2x^2+x-3x^3+6x-4\\\\=x^4-3x^3-2x^2+7x-4 \ \ \ so\\ \\\boxed{f'(x)=4x^3-9x^2-4x+7}

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

6 0
3 years ago
Hey you!!!! <br> Help me please
gizmo_the_mogwai [7]

Answer:

If the population has increased by 12% then to ensure a generated maximum capacity must be more than 12% we already have a figure being 100% prior so the answer is 12% population increase =112% and 12%.of 112 =13.44

We add this to 12

12+13.44= 25.44

Step-by-step explanation:

3 0
3 years ago
Assume that Santa has to deliver presents to almost 22 million kids an hour on the night before Christmas. What is his delivery
DENIUS [597]

Answer:

It's about 6,111 kids per second.

Step-by-step explanation:

1 hour = 60 minutes

1 minute = 60 seconds

60*60=3600

1 hour = 3600

hourly rate -> 22,000,000 kids/hr

secondly rate -> 22,000,000/3600 ≈ 6,111

secondly rate -> 6,111 kids/second

7 0
3 years ago
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