Answer:
See below
Step-by-step explanation:
The function
oscillates between -1 and 1, so the range is
.
Answer:
1) f(g(2)) = 24
2) f(g(-1)) = -4
Step-by-step explanation:
1) GIven f(x) = x²+2x and g(x) = 2x
f(g(x)) = f(2x)
f(2x) = (2x)² + 2(2x)
f(2x) = 4x² + 4x
f(g(x)) = 4x² + 4x
f(g(2)) = 4(2)² + 4(2)
f(g(2)) = 16+8
f(g(2)) = 24
2) f(x) = x+1 and g(x) = 5x
f(g(x)) = f(5x)
f(5x)= 5x + 1
f(g(x)) = 5x + 1
f(g(-1)) = 5(-1) + 1
f(g(-1)) = -5+1
f(g(-1)) = -4
For this case we have the following expression:
h (t) = - 16t ^ 2 + 122t + 10
We look for the maximum of the function, for this, we derive:
h '(t) = - 32t + 122
We match zero:
-32t + 122 = 0
We cleared t:
t = 122/32
t = 3.8125 s
Then, the maximum height will be:
h (3.8125) = - 16 * (3.2185) ^ 2 + 122 * (3.2185) +10
h (3.8125) = 236.92 feet
Answer:
It takes the boulder to reach maximum height about:
t = 3.8125 s
the boulders maximum height is:
236.92 feet
x² - x - 6 = (x +3)(x - 2)
x² - 5x + 6 = (x - 2)(x - 3)
What is their common factor?
Answer: B. x - 2