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3 years ago

The 7th grade has 386 students. There are 32 more girls than boys in the grade how many boys are in the 7th grade

Mathematics

2 answers:

alexandr402 [8]3 years ago

8 0

Answer:

there are 161 boys and 225 girls.

Zolol [24]3 years ago

3 0

Answer: 177 boys are in 7th grade.

Step-by-step explanation:

386-32= 354

354/2=177

177 +32= 209

177 boys and 209 girls

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Is this statement true or false 5/12 = 2/6

AveGali [126]

Answer:

False

Step-by-step explanation:

6*2= 12

So to get common denominators, you would need to divide 5/12 by 2 OF multiply 2/6 by 2

For the sake of ease just multiply 2/6 by 2, this will equal 4/12 NOT 5/12

Hope this helps! :)

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Step-by-step explanation: Hope this helps :)

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3 years ago

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Based on the given angle measures, which triangle has side length measures that could be correct?

Likurg_2 [28]

Answer

The triangle in the figure 4 is correct .

Reason

by using the trignometric identity

$tan\theta = \frac{Perpendicular}{Base}$

Thus

$tan 30^{\circ} = \frac{Perpendicular}{Base}$

$tan 30 ^{\circ} =\frac{1}{\sqrt{3}}$

Now in the figure (1)

$tan 30^{\circ} = \frac{13.9}{8}$

$\frac{1}{\sqrt{3}} = \frac{13.9}{8}$

on simplify

$0.5774 \neq 1.7375$

thus side length measures in the figure (1) is not correct .

Now in the figure (2)

$tan30^{\circ} =\frac{16}{8} \\ \frac{1}{\sqrt{3}} =\frac{16}{8} \\ 0.577 \neq 2$

thus side length measures in the figure (2) is not correct .

Now in the figure (3)

$tan 30 ^{\circ} = \frac{8}{16} \\ \frac{1}{\sqrt{3}} =\frac{8}{16} \\ 0.577\neq0.5$

thus side length measures in the figure (3) is not correct .

Now in the figure (4)

$tan30^{\circ} = \frac{8}{13.9} \\ \frac{1}{\sqrt{3}} =\frac{8}{13.9}\\ 0.577 = 0.576(approx)$

Therefore the figure (4) is correct triangle has side length measures that could be correct

Hence proved

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3 years ago

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baherus [9]

Answer:

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Step-by-step explanation:

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3 years ago

What is the area of this parallelogram?

Leokris [45]

Answer:

28 in²

Step-by-step explanation:

Area Parallelogram = b x h

Area Parallelogram = 4in x 7in

Area Parallelogram = 28 in²

-Chetan K

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3 years ago