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3 years ago

In 2004, Cindy had $4000 in a mutual fund account. In 2005, the

Mathematics

1 answer:

gtnhenbr [62]3 years ago

4 0

6,250
1,000/4,000 = 25/100
25/100 = x/5,000
x = 1,250

5,000 + 1,250 = 6,250

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What’s the percent of change?<br> Original: 25<br> New: 18

soldier1979 [14.2K]

28% decrease

Solution:

Calculate percentage change

from V1 = 25 to V2 = 18

(V2−V1)|V1|×100

=(18−25)|25|×100

=−725×100

=−0.28×100

=−28%change

=28%decrease

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3 years ago

What times what is 216

ElenaW [278]

2 times 108 is 216
3 times 72 is 216
4 times 54 is 216
6 times 36 is 216

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3 years ago

A number is multiplied by 6 and the result is 48. Find the number.

eduard

Answer:

the answer is 8

Step-by-step explanation:

8x6=48

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2 years ago

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A stationary store has decided to accept a large shipment of ball-point pens if an inspection of 17 randomly selected pens yield

Leno4ka [110]

Answer:

0.762 = 76.2% probability that this shipment is accepted

Step-by-step explanation:

For each pen, there are only two possible outcomes. Either it is defective, or it is not. The probability of a pen being defective is independent from other pens. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

17 randomly selected pens

This means that $n = 17$

(a) Find the probability that this shipment is accepted if 10% of the total shipment is defective. (Use 3 decimal places.)

This is $P(X \leq 2)$ when $p = 0.1$ . So

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{17,0}.(0.1)^{0}.(0.9)^{17} = 0.167$

$P(X = 1) = C_{17,1}.(0.1)^{1}.(0.9)^{16} = 0.315$

$P(X = 2) = C_{17,2}.(0.1)^{2}.(0.9)^{15} = 0.280$

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.167 + 0.315 + 0.280 = 0.762$

0.762 = 76.2% probability that this shipment is accepted

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3 years ago

What is the algebraic expression for the difference of 10-u

puteri [66]

I'm pretty sure that you answered it correctly. 10-U

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3 years ago

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