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sweet-ann [11.9K]
3 years ago
10

What is [(7x^3)(y^2)]^2/7 in radical form?

Mathematics
1 answer:
GuDViN [60]3 years ago
8 0
Remember
x^ \frac{m}{n} = \sqrt[n]{x^m}
and
(zy)^m=(z^m)(y^m)
and
(x^m)^n=x^(mn)

so
((7x^3)(y^2))^ \frac{2}{7} = \sqrt[7]{((7x^3)(y^2))^2}=
\sqrt[7]{((7x^3)^2(y^2)^2)}=
\sqrt[7]{((7^2x^6)(y^4))}=
\sqrt[7]{((49x^6)(y^4))}=
\sqrt[7]{49x^6y^4}
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Answer:

r = \$14.71

Step-by-step explanation:

Given

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