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Doss [256]
2 years ago
5

What information can be used to compare linear relationships? Explain why.

Mathematics
1 answer:
stellarik [79]2 years ago
8 0

Answer:the slope and the y intercept (you can tell there linear if the slope is the same and the y-intercepts are different).

Step-by-step explanation:

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How do you solve 6-9(4p-3)= 2(6p+7)+3
Alika [10]

Answer:

p=  1/3

​ =0.333

Step-by-step explanation:

Simplifying

6 + -9(4p + -3) = 2(6p + 7) + 3

Reorder the terms:

6 + -9(-3 + 4p) = 2(6p + 7) + 3

6 + (-3 * -9 + 4p * -9) = 2(6p + 7) + 3

6 + (27 + -36p) = 2(6p + 7) + 3

Combine like terms: 6 + 27 = 33

33 + -36p = 2(6p + 7) + 3

Reorder the terms:

33 + -36p = 2(7 + 6p) + 3

33 + -36p = (7 * 2 + 6p * 2) + 3

33 + -36p = (14 + 12p) + 3

Reorder the terms:

33 + -36p = 14 + 3 + 12p

Combine like terms: 14 + 3 = 17

33 + -36p = 17 + 12p

Solving

33 + -36p = 17 + 12p

Solving for variable 'p'.

Move all terms containing p to the left, all other terms to the right.

Add '-12p' to each side of the equation.

33 + -36p + -12p = 17 + 12p + -12p

Combine like terms: -36p + -12p = -48p

33 + -48p = 17 + 12p + -12p

Combine like terms: 12p + -12p = 0

33 + -48p = 17 + 0

33 + -48p = 17

Add '-33' to each side of the equation.

33 + -33 + -48p = 17 + -33

Combine like terms: 33 + -33 = 0

0 + -48p = 17 + -33

-48p = 17 + -33

Combine like terms: 17 + -33 = -16

-48p = -16

Divide each side by '-48'.

p = 0.3333333333

Simplifying

p = 0.3333333333

3 0
3 years ago
Read 2 more answers
Mohjjbn bn hjbjn hjbnm
Darya [45]
Yup yup, I understand your question: jejsusuehsbhs lakksjjwhe eiksjsjnesh is the answer you’re looking for. I’m happy to help
7 0
2 years ago
(3x³+3x²-4×+5)+(x³-2x²+x-4)​
Harman [31]

s

Step-by-step explanation:

no lo  se qra perdon mi no me aenseñaronu eese tema :ec

se

3 0
3 years ago
How do you evaluate sin(13π/12)?
Alekssandra [29.7K]

13pi/12 lies between pi and 2pi, which means sin(13pi/12) < 0

Recall the double angle identity,

sin^2(x) = (1 - cos(2x))/2

If we let x = 13pi/12, then

sin(13pi/12) = - sqrt[(1 - cos(13pi/6))/2]

where we took the negative square root because we expect a negative value.

Now, because cosine has a period of 2pi, we have

cos(13pi/6) = cos(2pi + pi/6) = cos(pi/6) = sqrt[3]/2

Then

sin(13pi/12) = - sqrt[(1 - sqrt[3]/2)/2]

sin(13pi/12) = - sqrt[2 - sqrt[3]]/2

7 0
3 years ago
What is the slope of a trend line that passes through the points (5, 80) and (7, 65)?
Vlad [161]

Answer:

-15/2 or -7.5 or -7½

Negative StartFraction 15 Over 2 EndFraction

Step-by-step explanation:

Slope or gradient of a line is the ratio of change in y co-ordinates to the change in x co-ordinates.

Therefore;

M=∆y÷∆x

The change in y co-ordinates is given by

∆y=y2-y1

Similarly, change in x co-ordinates is given by

∆x=x2-x1

Given the two points as (5, 80) and (7, 65)

X1=5 Y1=80

X2=7 Y2=65

∆y=65-80=-15

∆x=7-5=2

Hence ∆y÷∆x will be -15÷2=-7.5 or -7½

Negative StartFraction 15 Over 2 EndFraction

4 0
3 years ago
Read 2 more answers
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