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3 years ago

Quadrilateral ABCD is inscribed. The measure of ZA = 67º. What is the measure of ZC?

Mathematics

1 answer:

Luda [366]3 years ago

7 0

Answer:

m<C = 113°

Step-by-step explanation:

m<A = 67° (given)

Recall: opposite angles in any inscribed quadrilateral in a circle are equal to 180° or are supplements of one another.

This implies that:

m<A + m<C = 180°

Substitute

67° + m<C = 180°

Subtract 67° from each side

m<C = 180° - 67°

m<C = 113°

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Use the table to identify the values of p and q that should be used to factor x^2+9x-10 as (x+p)(x+q)

likoan [24]

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p = -1 and q = 10
answer is A.

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X2+8x=-1 complete the square

Sophie [7]

(X+4)^2-15

This is the answer

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3 years ago

What is 4.3(v+2.5)=8.11+4v

True [87]

Answer:

-8.8

Step-by-step explanation:

We begin by simplifying the parenthesis through multiplication. Parenthesis is a structure which signals multiplication happening.

$4.3(v+2.5)=8.11+4v\\4.3v+10.75=8.11+4v$

We now begin combining like terms across the equal sign by performing the inverse or doing the opposite. Move first the 8.11 by subtracting it from both sides.

$4.3v+10.75-8.11=8.11-8.11+4v\\4.3v+2.64=4v$

Now, move 4.3v across by subtracting it from both sides.

$4.3v-4.3v+2.64=4v-4.3v$

$2.64=-0.3v$

Finally, we divide both sides by the coefficient of v.

$\frac{2.64}{-0.3} =\frac{-0.3v}{-0.3} \\-8.8=v$

6 0

3 years ago

Can someone help me please !

elena55 [62]

The reference angle is
pi/3.

At 180 it would be 9pi/3 so going past that is 10pi/3.

7 0

3 years ago

Pleaseee helppppppppppppppppppp

quester [9]

To find Angle A we use cosine

cos ∅ = adjacent / hypotenuse

From the question

The adjacent is 17

The hypotenuse is 38

So we have

cos A = 17/38

A = cos-¹ 17/38

A = 63.4

<h3>A = 63° to the nearest degree</h3>

To find Angle C we use sine

sin ∅ = opposite / hypotenuse

From the question

The opposite is 17

The hypotenuse is 38

So we have

sin C = 17/38

C = sin-¹ 17/38

C = 26.57

<h3>C = 27° to the nearest degree</h3>

Hope this helps you

7 0

3 years ago