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Grace [21]
3 years ago
5

Explain how you would know log3100 is between 4 and 5 without the use of a calculator.

Mathematics
1 answer:
natulia [17]3 years ago
6 0
\log{3100}=\log{(100\times 31)}=\log{100}+\log{31}=\log{10^2}+\log{31}=
\\ =2\log{10}+\log{31}=2\times1+\log{31}=2+\log{31}
\\
\\ 2+\log{10}\ \textless \ 2+\log{31}\ \textless \ 2+\log{100}
\\ 2+\log{10}\ \textless \ 2+\log{31}\ \textless \ 2+\log{10^2}
\\ 2+\log{10}\ \textless \ 2+\log{31}\ \textless \ 2+2\log{10}
\\ 2+1\ \textless \ 2+\log{31}\ \textless \ 2+2\times 1
\\ 3\ \textless \ 2+\log{31}\ \textless \ 4
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3 years ago
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3 years ago
[REALLY EASY QUESTION]
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8 0
2 years ago
The graph of a relation must pass the vertical line test.<br><br> True or false
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4 0
3 years ago
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