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crimeas [40]
3 years ago
15

Identify an equation in slope-intercept form for the line parallel to y = 5x + 2 that passes through (-6,-1)

Mathematics
1 answer:
ikadub [295]3 years ago
3 0

Answer:

y=5x+29

Step-by-step explanation:

y=mx+b

Since the line is parallel, the slope, m, will be the same.

Use the point provided to find the y-intercept b:

-1=5(-6)+b

-1=-30+b

b=29

Now, we rewrite the equation:

y=5x+29

You might be interested in
[4 - (3c - 1)][6 - ( 3c - 1)]
Anestetic [448]
Hi there!

You would have to simplify the terms inside [ ] this thing, then multiply.

So let's simplify them first.

4 - (3c - 1) 
use distributive property.....
4 - 3c + 1
-3c + 5

6 - (3c - 1)
use distributive property again...
6 - 3c + 1
-3c + 7

so now, multiply (-3c + 5)(-3c + 7).
(-3c + 5)(-3c + 7)
9c² - 21c - 15c + 35
9c² - 36c + 35

So your final answer is...
9c² - 36c + 35

Hope this helped! :)
3 0
3 years ago
Read 2 more answers
A group of students is collecting books to add to their
pentagon [3]

Answer:(2,23) & (7,48)

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
HELP PLS
Neko [114]
Expansions and compressions are transformations that change the length or width of the graph of a function.


 To graph y = a*f (x)
 if a> 1, the graph of y = f (x) is expanded vertically by a factor a. 
 We have then:
 f (x) = 2/5 x ^ 2-2
 The function g (x) is a vertical stretch of f (x) by a factor of 2:
 g (x) = 2f (x)
 g (x) = 2 (2/5 x ^ 2-2)
 g (x) = 4/5 x ^ 2-4

 Answer:
 The equation of g (x) is: 
 g (x) = 4/5 x ^ 2-4
8 0
2 years ago
Construct a quadrilateral MINT such that MI= 5cm, IN = 6cm, NT = 7cm, TM=3cm and MN =9cm
Tems11 [23]

From the given dimensions, of MI, IN, NT, TM, and MN, the quadrilateral

MINT can be drawn as shown in the attached image.

<h3>What are the steps for the construction of MINT?</h3>

The given dimensions of the quadrilateral MINT are;

MI = 5 cm

IN = 6 cm

NT = 7 cm

TM = 3 cm

MN = 9 cm

The side MN is a diagonal of MINT, therefore;

ΔMIN, and ΔMTN are triangles with a common base = MN

The steps to construct MINT are therefore;

  • Step 1; Draw the line MN = 9 cm.

  • Step 2; Place the compass at point <em>M</em> and with a radius MI = 5 cm, draw an arc on one side of MN.

  • Step 3; Place the compass at <em>N</em> and with radius IN = 6 cm, draw an arc to intersect the arc dawn in step 1 above.

  • Step 4; Place an arc at point <em>M</em> and with radius TM = 3 cm draw an arc on the other side of MN.

  • Step 5; Place the compass at point <em>N</em> and with radius NT = 7 cm, draw an arc to intersect the arc drawn in step 3.

  • Step 6; Join the point of intersection of the arcs to points <em>M</em> and <em>N</em> to complete the quadrilateral MINT.

Please find attached the drawing (showing the construction arcs) of the

quadrilateral MINT created with MS Word.

Learn more about types of geometric construction here:

brainly.com/question/785568

brainly.com/question/8607612

6 0
1 year ago
Can 231,000 be written as 0.23
aivan3 [116]
Ur close but it is 0.023 you were off just a bit
3 0
3 years ago
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