3 years ago

Identify an equation in slope-intercept form for the line parallel to y = 5x + 2 that passes through (-6,-1)

Mathematics

1 answer:

ikadub [295]3 years ago

3 0

Answer:

$y=5x+29$

Step-by-step explanation:

$y=mx+b$

Since the line is parallel, the slope, m, will be the same.

Use the point provided to find the y-intercept b:

$-1=5(-6)+b$

$-1=-30+b$

$b=29$

Now, we rewrite the equation:

$y=5x+29$

You might be interested in

What is the domain for y=2x

Snowcat [4.5K]

Answer:

y ...................

7 0

3 years ago

Emma drew 2 hearts and 37 circles. What is the ratio of circles to all shapes?

Schach [20]

Answer:

37:39

Step-by-step explanation:

You write the amount of circles then add 37 to 2 and make a ratio table.

4 0

3 years ago

Read 2 more answers

Albert needs to make a grade of more than 90 to get an a in his math class

tia_tia [17]

Yeah I’m just like Albert

6 0

2 years ago

For a function g(x), the difference quotient is StartFraction 6 Superscript x + h minus 3 Baseline minus 6 Superscript x + 3 Bas

kobusy [5.1K]

Answer:

The average rate of change in that interval is 1.99

Step-by-step explanation:

Here we have that the difference quotient for g(x) is:

$\frac{6^{x + h} - 3 - 6^x + 3}{h}$

Remember that for a general function f(x), the difference quotient is:

$\frac{f(x + h) - f(x)}{h}$

So if we look at the difference quotient for g(x), we can conclude that:

$g(x) = 6^x - 3$

Also remember that the average rate of change in an interval (a, b) is just:

$\frac{g(b) - g(a)}{b - a}$

So here we want the average rate of change of g(x) in the interval from x = -2 to x = 1, this is:

$R = \frac{(6^1 - 3) - (6^{-2} - 3)}{1 - (-2)} = \frac{6 - 6^{-2}}{3} = 1.99$

The average rate of change in that interval is 1.99

8 0

3 years ago

PLEASE HELP ME IDK THE ANSWER PLEASE

Klio2033 [76]

The answer would be 9.2

8 0

3 years ago