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3 years ago

What is the value of the expression 4(x - y) + 2 when x = 7 and y = 1?

Mathematics

2 answers:

Ksju [112]3 years ago

7 0

Answer:

Step-by-step explanation:

4(7-1) +2

4(6) + 2

24+ 2

lesya [120]3 years ago

3 0

Answer: 26

Step-by-step explanation:

4(x-y)+2

Lets plug in 7 for x and 1 for y

4(7-1)+2=4(6)+2

4*6=24

24+2=26

26 is the answer

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5-7 <-3 : what is the simplified form of the inequality below ?

Makovka662 [10]

Answer:

5<4

Step-by-step explanation:

This inequality is not correct though.

5-7+7<-3+7

5<4

7 0

3 years ago

Can yall please help me, try to explain in steps, tyy

almond37 [142]

Answer:

b. would be the answer bc it goes in a line if you were to connect the dots

8 0

3 years ago

Nadia is a stockbroker. She earns 13% commission each week. Last week, she sold $4,500 worth of stocks. How much did she make

m_a_m_a [10]

Multiply amount sold by commission rate:

4500 x 0.13 = 585

She made $585 last week.

Multiply amount made in 1 week by 52 weeks ( 1 year = 52 weeks)

585 x 52 = 30,420

She made $30,420 in 2011

6 0

3 years ago

an inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a

viktelen [127]

Answer:

the rate of change of the water depth when the water depth is 10 ft is; $\mathbf{\dfrac{dh}{dt} = \dfrac{-25}{100 \pi} \ \ ft/s}$

Step-by-step explanation:

Given that:

the inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec.

We are meant to find the rate of change of the water depth when the water depth is 10 ft.

The diagrammatic expression below clearly interprets the question.

From the image below, assuming h = the depth of the tank at a time t and r = radius of the cone shaped at a time t

Then the similar triangles ΔOCD and ΔOAB is as follows:

$\dfrac{h}{r}= \dfrac{20}{8}$ ( similar triangle property)

$\dfrac{h}{r}= \dfrac{5}{2}$

$\dfrac{h}{r}= 2.5$

h = 2.5r

$r = \dfrac{h}{2.5}$

The volume of the water in the tank is represented by the equation:

$V = \dfrac{1}{3} \pi r^2 h$

$V = \dfrac{1}{3} \pi (\dfrac{h^2}{6.25}) h$

$V = \dfrac{1}{18.75} \pi \ h^3$

The rate of change of the water depth is :

$\dfrac{dv}{dt}= \dfrac{\pi r^2}{6.25}\ \dfrac{dh}{dt}$

Since the water is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec

Then,

$\dfrac{dv}{dt}= - 4 \ ft^3/sec$

Therefore,

$-4 = \dfrac{\pi r^2}{6.25}\ \dfrac{dh}{dt}$

the rate of change of the water at depth h = 10 ft is:

$-4 = \dfrac{ 100 \ \pi }{6.25}\ \dfrac{dh}{dt}$

$100 \pi \dfrac{dh}{dt} = -4 \times 6.25$

$100 \pi \dfrac{dh}{dt} = -25$

$\dfrac{dh}{dt} = \dfrac{-25}{100 \pi}$

Thus, the rate of change of the water depth when the water depth is 10 ft is; $\mathtt{\dfrac{dh}{dt} = \dfrac{-25}{100 \pi} \ \ ft/s}$

4 0

4 years ago

Which equation is equivalent to log^x36=2?

Dennis_Churaev [7]

The equation which is equivalent to $\log _{x} 36=2$ is $x^{2}=36$ or x = 6 ( $\log _{6} 36=2$ ).

<u>Step-by-step explanation:</u>

Given Equation:

$\log _{x} 36=2$

As we know, in terms of logarithmic rules, when b is raised to the power of y is equal x:

$b^{y}=a$

Then, the base b logarithm of x is equal to y

$\log _{b}(x)=y$

Now, use the logarithmic rule for the given equation by comparing with above equation. We get b = x, y = 2, and x = 36. Apply this in equation,

$b^{y}=a$

$x^{2}=36$

When taking out the squares on both sides, we get x = 6. Hence, the given equation can be written as $\log _{6} 36=2$

8 0

3 years ago

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