You are right. In circle equation we have =r² so the correct answer will be C od D. But we have to calculate the center of a circle.
![x^2+y^2-8x-6y+24=0\quad|-24\\\\(x^2-8x)+(y^2-6y)=-24](https://tex.z-dn.net/?f=x%5E2%2By%5E2-8x-6y%2B24%3D0%5Cquad%7C-24%5C%5C%5C%5C%28x%5E2-8x%29%2B%28y%5E2-6y%29%3D-24)
Complete the square:
![x^2-8x+a^2\implies a=\dfrac{8x}{2x}=4\implies x^2-8x+4^2\\\\\\y^2-6y+b^2\implies b=\dfrac{6y}{2y}=3\implies y^2-6y+3^2](https://tex.z-dn.net/?f=x%5E2-8x%2Ba%5E2%5Cimplies%20a%3D%5Cdfrac%7B8x%7D%7B2x%7D%3D4%5Cimplies%20x%5E2-8x%2B4%5E2%5C%5C%5C%5C%5C%5Cy%5E2-6y%2Bb%5E2%5Cimplies%20b%3D%5Cdfrac%7B6y%7D%7B2y%7D%3D3%5Cimplies%20y%5E2-6y%2B3%5E2)
And we have:
![(x^2-8x)+(y^2-6y)=-24\\\\(x^2-8x+4^2)-4^2+(y^2-6y+3^2)-3^2=-24\\\\ (x-4)^2+(y-3)^2-16-9=-24\\\\(x-4)^2+(y-3)^2-25=-24\quad|+25\\\\\boxed{(x-4)^2+(y-3)^2=1}](https://tex.z-dn.net/?f=%28x%5E2-8x%29%2B%28y%5E2-6y%29%3D-24%5C%5C%5C%5C%28x%5E2-8x%2B4%5E2%29-4%5E2%2B%28y%5E2-6y%2B3%5E2%29-3%5E2%3D-24%5C%5C%5C%5C%0A%28x-4%29%5E2%2B%28y-3%29%5E2-16-9%3D-24%5C%5C%5C%5C%28x-4%29%5E2%2B%28y-3%29%5E2-25%3D-24%5Cquad%7C%2B25%5C%5C%5C%5C%5Cboxed%7B%28x-4%29%5E2%2B%28y-3%29%5E2%3D1%7D)
So the answer is C (the same left side of equation).
Answer:
£20
Step-by-step explanation:
First you add 1 ,1 ,2 which =4
Next you divide 80 by 4 which give you the answer 20.
So first you need to factor and get 8( t-1 ) (2t+1)=0. Then you need to divide both sides by 8 to isolate the equation. 0/8=0 so ( t-1 ) (2t+1)=0. Next set each of the factors = to 0 and get t-1=0 and 2t+1=0. Solve, and get t=1 and t=-1/2. The negative does not apply so you know it takes 1 second for the ball to hit the ground.
Answer:1
Step-by-step explanation:
hello there the answer is there are
29 ways
hope this helped