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Makovka662 [10]
3 years ago
6

How many one-to-one correspondences exist between A = {1, 2, 3, 4} and B = {a, b, c, d}

Mathematics
1 answer:
aleksklad [387]3 years ago
5 0

Answer:

There are 24 different correspondences.

Step-by-step explanation:

A one-to-one correspondence means that each element of A can be mapped into only one element of B, and we can't have two or more elements from A mapped into one element from B.

So, to count all the possible combinations, we need to find the number of possible options for each mapping

The first element from A, the 1, can be mapped into any of the four elements of B, so here we have 4 options.

The second element from A, the 2, can be mapped into any of the remaining elements from B, 3 of them (remember that one of the elements of B is taken).

The third element from A, the 3, can be mapped into any of the remaining elements from B, 2 of them now, so here we have 2 options.

The final element from A, the 4, can be mapped into the remaining element from B, so here we have only one option.

The total number of different correspondences (or combinations) is equal to the product between the numbers of options, this is:

Combinations = 4*3*2*1 = 12*2 = 24

There are 24 different correspondences.

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Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be
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<h2>Hello!</h2>

The answer is:

FirstCarSpeed=41mph\\SecondCarSpeed=55mph

<h2>Why?</h2>

To calculate the speed of the cars, we need to write two equations in order to create a relation between the two speeds and be able to isolate one in function of the other.

So, let be the first car speed "x" and the second car speed "y", writing the equations we have:

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x_{FirstCar}=x_o+v*t

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

x_{SecondCar}=x_o+(v+14mph)*t

Now, we already know that both cars met after 2 hours and 45 minutes, meaning that positions will be the same at that moment, and the distance between A and B is 264 miles,  so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph

Then, since we know that they covered a combined distance which is equal to 264 miles of distance in 2 hours + 45 minutes, we  have:

2hours+45minutes=120minutes+45minutes=165minutes\\\\\frac{165minutes*1hour}{60minutes}=2.75hours

Writing the equation, we have:

264miles=(2x+14mph)*t\\\\264miles=(2x+14mph)*2.75hours\\\\2x+14mph=\frac{264miles}{2.75hours}\\\\2x=96mph-14mph\\\\x=\frac{82mph}{2}=41mph

We have that the speed of the first car is equal to 41 mph.

Now, for the second car we have that:

SecondCarSpeed=FirstCarSpeed+14mph\\\\SecondCarSpeed=41mph+14mph=55mph

Hence, we have that:

FirstCarSpeed=41mph\\SecondCarSpeed=55mph

Have a nice day!

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