Which option identifies the goal in the user story in the following scenario?
2 answers:
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The classical motion for an oscillator that starts from rest at location x₀ is
x(t) = x₀ cos(ωt)
The probability that the particle is at a particular x at a particular time t
is given by ρ(x, t) = δ(x − x(t)), and we can perform the temporal average
to get the spatial density. Our natural time scale for the averaging is a half
cycle, take t = 0 → π/ ω
Thus,
ρ =
Limit is 0 to π/ω
We perform the change of variables to allow access to the δ, let y = x₀ cos(ωt) so that
ρ(x) =
Limit is x₀ to -x₀
Limit is -x₀ to x₀
This has as expected. Here the limit is -x₀ to x₀
The expectation value is 0 when the ρ(x) is symmetric, x ρ(x) is asymmetric and the limits of integration are asymmetric.
The friction force f = 10000 N
The heat transfer Q = 1.7936 KJ
<u>Explanation:</u>
Given data:
Surface area of Piston = 1
Volume of saturated water vapor = 100 K Pa
Steam volume = 0.05
Using the table of steam at 100 K pa
Steam density = 0.590 Kg/
Specific heat = 2.0267 KJ/Kg K
Mass of vapor = S × V
m = 0.590 × 0.05
m = 0.0295 Kg
Solution:
a) The friction force is calculated
Friction force = In the given situation, the force need to stuck the piston.
= pressure inside the cylinder × piston area
= 100 × × 0.1
f = 10000 N
b) To calculate heat transfer.
Heat transfer = Heat needs drop temperatures 30°C.
Q = 0.0295 × 2.0267 × × 30
Q = 1.7936 KJ