Answer:
The maximum length of a surface flaw that is possible without fracture is
Explanation:
The given values are,
σ=1.65 MPa
γs=0.60 J/m2
E= 2.0 GPa
The maximum possible length is calculated as:
The maximum length of a surface flaw that is possible without fracture is
No ground to connect to show me attach to any terminal or lead size reverse designated polarity
Answer B.False
Answer:
14.506°C
Explanation:
Given data :
flow rate of water been cooled = 0.011 m^3/s
inlet temp = 30°C + 273 = 303 k
cooling medium temperature = 6°C + 273 = 279 k
flow rate of cooling medium = 0.02 m^3/s
Determine the outlet temperature
we can determine the outlet temperature by applying the relation below
Heat gained by cooling medium = Heat lost by water
= ( Mcp ( To - 6 ) = Mcp ( 30 - To )
since the properties of water and the cooling medium ( water ) is the same
= 0.02 ( To - 6 ) = 0.011 ( 30 - To )
= 1.82 ( To - 6 ) = 30 - To
hence To ( outlet temperature ) = 14.506°C
Answer:
Explanation:
Given: Pressure of a fluid column ΔP=ρgΔh
Density of water (ρ) = 1000 kg/m^3
Acceleration of gravity (g) = 9.8 m/sec^2
Δh = difference in height / elevation of water tower and tap
= 50 - 10
= 40
Substitute back into equation:
Pressure = 1000*9.8*40
= 392000 N/m^2
The answer is D.
