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mr_godi [17]
3 years ago
7

What is meant by solvation?

Chemistry
1 answer:
Kamila [148]3 years ago
6 0
Solvation describes the interaction of solvent with dissolved molecules.
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If the volume of a confined gas is doubled while the temperature remain constant, what change (if any) would be observed in the
dimulka [17.4K]

The gas will obey Boyles Law:

P1 V1 = P2 V2      where P1 and V1 are the original pressure and volume and P2 and V2 are the new  values.

If V2 = 2V1  (given) then:

P1 V1 = P2 *2 V1

P2 = P1 V1 / 2V1

P2 = P1 / 2

In other words the pressure is halved. (answer).

3 0
4 years ago
Read 2 more answers
BRAINLIEST Give examples of at least three critical questions of society that science can help answer.
ICE Princess25 [194]

Answer:

1. How did life begin?

2. Are we alone in the universe?

3. What makes us human?

3 0
3 years ago
Object A has a mass of 3,600 kilograms. Object B has a mass of 600 kilograms. The weight of Object B will be ________ times the
Natalija [7]

Hi the answer is 1/6, because 1/6 of 3,600 is 600, so it's 1/6. Have a great day!


7 0
3 years ago
A certain first order reaction has a half-life of 54. 3 s. How long will it take (in s) for the reactant concentration to decrea
Maksim231197 [3]

Answer:

82.4 s

Explanation:

Find the NUMBEr of half lives...then multiply by 54.3

2.27 = 6.5 (1/2)^n

log (2.27/6.5) / log (1/2) = n = 1.52 half lives

1.52 * 54.3 = 82.4 s

8 0
2 years ago
If a gas occupies 1532.7 mL at standard temperature, what volume does it occupy at 49.4 ºC if the pressure remains constant?
ElenaW [278]

Answer:

a. 1810mL

Explanation:

When conditions for a gas change under constant pressure (and the number of molecules doesn't change), it follows Charles' Law:

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}  where the temperatures must be measured in Kelvin

To convert from Celsius to Kelvin, add 273, or use the equation:  T_C+273=T_K

For this problem, one must also recall that standard temperature is 0°C (or 273K).

So, T_1 = 273[K], and T_2 = (49.4+273)[K]=322.4[K].

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

\dfrac{(1532.7[mL])}{(273[K])}=\dfrac{V_2}{(322.4[K])}

\dfrac{(1532.7[mL])}{(273[K\!\!\!\!\!{-}])}(322.4[K\!\!\!\!\!{-}] )=\dfrac{V_2}{(322.4[K]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----})}(322.4[K]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----})

1810.04571428[mL]=V_2

Adjusting for significant figures, this gives V_2=1810[mL]

4 0
2 years ago
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