Question

Solid aluminum hydroxide is added to a solution of potassium phosphite.

Answer 1

Answer :

• The complete balanced equation will be,

$Al(OH)_3(aq)+K_3PO_3(aq)\rightarrow AlPO_3(s)+3KOH(aq)$

• The complete ionic equation in separated aqueous solution will be,

$Al^{3+}(aq)+3OH^{-}(aq)+3K^{+}(aq)+PO_3^{3-}(aq)\rightarrow AlPO_3(s)+2K^+(aq)+3OH^{-}(aq)$

• The net ionic equation will be,

$Al^{3+}(aq)+PO_3^{3-}(aq)\rightarrow AlPO_3(s)$

Explanation :

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The complete balanced equation will be,

$Al(OH)_3(aq)+K_3PO_3(aq)\rightarrow AlPO_3(s)+3KOH(aq)$

The complete ionic equation in separated aqueous solution will be,

$Al^{3+}(aq)+3OH^{-}(aq)+3K^{+}(aq)+PO_3^{3-}(aq)\rightarrow AlPO_3(s)+2K^+(aq)+3OH^{-}(aq)$

In this equation, $K^+\text{ and }OH^-$ are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

$Al^{3+}(aq)+PO_3^{3-}(aq)\rightarrow AlPO_3(s)$