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Darya [45]
3 years ago
12

What is the estimate of 27,865

Mathematics
2 answers:
Vladimir [108]3 years ago
7 0
The estimate of 27,865 is 28,000.
Savatey [412]3 years ago
4 0
28,000 .........................................................
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The diagnols of a rhombus are 21 and 16 centimeters long find the area of the rhombus
mr_godi [17]

Answer:

  168 cm²

Step-by-step explanation:

The area of a quadrilateral with diagonals that intersect at right angles is half the product of the lengths of the diagonals. A rhombus is one such quadrilateral, so the area of this one is ...

  A = 1/2(d1)(d2)

  A = (1/2)(21 cm)(16 cm) = 168 cm²

The area of the rhombus is 168 cm².

8 0
3 years ago
Determine whether the function is continuous or discontinuous.
shusha [124]

Answer:

it is continues

Step-by-step explanation:

it is continues

6 0
3 years ago
I need help please??!!
storchak [24]

Answer:

No.

Step-by-step explanation:

The x coordinate of the equation is 1/2, so x cannot be 0.

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4 years ago
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Use the definition of continuity and the properties of limit to show that the function f(x)=x sqrtx/ (x-6)^2 is continuous at x=
jasenka [17]

Answer:

The function \\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}} is continuous at x = 36.

Step-by-step explanation:

We need to follow the following steps:

The function is:

\\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}

The function is continuous at point x=36 if:

  1. The function \\ f(x) exists at x=36.
  2. The limit on both sides of 36 exists.
  3. The value of the function at x=36 is the same as the value of the limit of the function at x = 36.

Therefore:

The value of the function at x = 36 is:

\\ f(36) = \frac{36*\sqrt{36}}{(36-6)^{2}}

\\ f(36) = \frac{36*6}{900} = \frac{6}{25}

The limit of the \\ f(x) is the same at both sides of x=36, that is, the evaluation of the limit for values coming below x = 36, or 33, 34, 35.5, 35.9, 35.99999 is the same that the limit for values coming above x = 36, or 38, 37, 36.5, 36.1, 36.01, 36.001, 36.0001, etc.

For this case:

\\ lim_{x \to 36} f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}

\\ \lim_{x \to 36} f(x) = \frac{6}{25}

Since

\\ f(36) = \frac{6}{25}

And

\\ \lim_{x \to 36} f(x) = \frac{6}{25}

Then, the function \\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}} is continuous at x = 36.

8 0
3 years ago
A dot plot shows the<br> on a number line.<br> symmetry<br> cluster<br> frequency of data
Alecsey [184]

Answer:

Frequency

Step-by-step explanation:

"A dot plot is a visual display in which each piece of data is represented by a dot above a number line, showing the frequency of each data value. The total number of dots in the plot is the total number of values in the data set. The data points must all be in the same units."

8 0
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