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marta [7]
3 years ago
14

If (-2,11)and(9,22) are two anchor points on the trend line, then find the equation of the line​

Mathematics
1 answer:
Elza [17]3 years ago
4 0

Answer:

The equation of the line is y=x+13

Step-by-step explanation:

step 1

Find the slope

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

we have

(-2,11) and (9,22)

substitute

m=\frac{22-11}{9+2}

m=\frac{11}{11}

m=1

step 2

Find the equation in slope intercept form

y=mx+b

where

m is the slope

b is the y-intercept

we have

m=1

point\ (-2,11)

substitute in the equation and solve for b

11=(1)(-2)+b

11=-2+b

Adds 2 both sides

b=11+2\\b=13

The equation of the line is

y=x+13

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Rosie washes clothes for two families the first family pays her $500 more per month than the second. Her total earning per month
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Answer:

  • Family 1:  $1.850
  • Family 2: $1.350

Step-by-step explanation:

We know that the total monthly payment is 3200, so if we call Pa (family A`s payment) and Pb (Family B's payment) the payments:

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  • also, Pa = Pb+500

So if we replace Pa in the first ecuation:

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then Pa+Pb=3200 => Pa= 3200-1350= $1.850

Good Luck!

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What is the 8th term of this sequence 2,8,18,36,66, 112,178
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Although cities encourage carpooling to reduce traffic congestion, most vehicles carry only one person. For example, 64% of vehi
ira [324]

Answer:

a) 0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

b) 0.996 is the probability that more than half of the vehicles  carry just one person.    

Step-by-step explanation:

We are given the following information:

A) Binomial distribution

We treat vehicle on road with one passenger as a success.

P(success) = 64% = 0.64

Then the number of vehicles follows a binomial distribution, where

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 10

We have to evaluate:

P(x \geq 6) = P(x =6) +...+ P(x = 10) \\= \binom{10}{6}(0.64)^6(1-0.64)^4 +...+ \binom{10}{10}(0.64)^{10}(1-0.79)^0\\=0.7291

0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

B) By normal approximation

Sample size, n = 92

p = 0.64

\mu = np = 92(0.64) = 58.88

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We have to evaluate the probability that more than 47 cars carry just one person.

P(x \geq 47)

After continuity correction, we will evaluate

P( x \geq 46.5) = P( z > \displaystyle\frac{46.5 - 58.88}{4.60}) = P(z > -2.6913)

= 1 - P(z \leq -2.6913)

Calculation the value from standard normal z table, we have,  

P(x > 46.5) = 1 - 0.004 = 0.996 = 99.6\%

0.996 is the probability that more than half out of 92 vehicles carry just one person.

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Answer:

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Step-by-step explanation:

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y = 12/5

y = 2.4

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