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Crank
3 years ago
5

Twice a number increased by 5?? in algebraic expression

Mathematics
2 answers:
Brut [27]3 years ago
7 0

To write this as an algebraic expression, remember that twice a number means that 2 is being multiplied by a number. Since we are not solving, we can just use the variable n to represent the number that is being multiplied by 2. Finally, adding 5 to the number we will get the expression 2n + 5.

Romashka [77]3 years ago
6 0
2x+5 would be the equation

x is the "number" that is unknown, it's what's called a variable. Because you need two times a number(x) you put a coefficient of 2 in front of it, then simply add 5.

Examples with known variable values:
2(4)+5=13
2(2)+5=9
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A(1)=20
Paladinen [302]

Answer:

-14

Step-by-step explanation:

You've got a(1)=20

a(1) means a(n) when n=1

the sequence is telling you to take the previous value of a(n), which is a(n-1) and subtract 17

then:

a(2) = a(1)-17 = 20 - 17 = 3

a(3) = a(2) - 17 = 3-17 = -14

3 0
3 years ago
An urn contains nine red and one blue balls. A second urn contains one red and five blue balls. One ball is removed from each ur
il63 [147K]

Answer:

0.362

Step-by-step explanation:

When drawing randomly from the 1st and 2nd urn, 4 case scenarios may happen:

- Red ball is drawn from the 1st urn with a probability of 9/10, red ball is drawn from the 2st urn with a probability of 1/6. The probability of this case to happen is (9/10)*(1/6) = 9/60 = 3/20 or 0.15. The probability that a ball drawn randomly from the third urn is blue given this scenario is (1 blue + 5 blue)/(8 red + 1 blue + 5 blue) = 6/14 = 3/7.

- Red ball is drawn from the 1st urn with a probability of 9/10, blue ball is drawn from the 2nd urn with a probability of 5/6. The probability of this event to happen is (9/10)*(5/6) = 45/60 = 3/4 or 0.75. The probability that a ball drawn randomly from the third urn is blue given this scenario is (1 blue + 4 blue)/(8 red + 1 blue + 1 red + 4 blue) = 5/14

- Blue ball is drawn from the 1st urn with a probability of 1/10, blue ball is drawn from the 2nd urn with a probability of 5/6. The probability of this event to happen is (1/10)*(5/6) = 5/60 = 1/12. The probability that a ball drawn randomly from the third urn is blue given this scenario is (4 blue)/(9 red + 1 red + 4 blue) = 4/14 = 2/7

- Blue ball is drawn from the 1st urn with a probability of 1/10, red ball is drawn from the 2st urn with a probability of 1/6. The probability of this event to happen is (1/10)*(1/6) = 1/60. The probability that a ball drawn randomly from the third urn is blue given this scenario is (5 blue)/(9 red + 5 blue) = 5/14.

Overall, the total probability that a ball drawn randomly from the third urn is blue is the sum of product of each scenario to happen with their respective given probability

P = 0.15(3/7) + 0.75(5/14) + (1/12)*(2/7) + (1/60)*(5/14) = 0.362

8 0
2 years ago
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Step-by-step explanation:

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2 years ago
Easy one - giving brainly if correct - show work.​
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so total money is 60000 - 9000

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4 0
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