2 years ago

Hey! may you please check if this is right, and if wrong give me the right answer?

1 answer:

Rudiy272 years ago

4 0

Answer:

I think it is true , but I am not sure

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Nana76 [90]

Look at the picture.

$\csc\theta=\dfrac{1}{\sin\theta}=\dfrac{1}{\frac{y}{r}}=\dfrac{r}{y}$

We have the right triangle x, y and r. From the Pythagorean theorem we have:

$r^2=x^2+y^2\to r=\sqrt{x^2+y^2}$

We have the point

$\left(-\dfrac{2}{3};\ \dfrac{\sqrt5}{3}\right)$

Substitute:

$r=\sqrt{\left(-\dfrac{2}{3}\right)^2+\left(\dfrac{\sqrt5}{3}\right)^2}\\\\r=\sqrt{\dfrac{4}{9}+\dfrac{5}{9}}\\\\r=\sqrt{\dfrac{9}{9}}\\\\r=1$

$\csc\theta=\dfrac{1}{\frac{\sqrt5}{3}}=\dfrac{3}{\sqrt5}=\dfrac{3\cdot\sqrt5}{\sqrt5\cdot\sqrt5}=\boxed{\dfrac{3\sqrt5}{5}}$

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3 years ago

Svetllana [295]

X=42.15-20.00y
this is in x=y

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3 years ago

zvonat [6]

$469,300 is the answer for my K12 homie

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3 years ago

cestrela7 [59]

Answer: No.

Good luck! I hope this is right!

6 0

3 years ago

Finger [1]

Answer: The answer is B

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2 years ago

Hey! may you please check if this is right, and if wrong give me the right answer?​