$\text{Let it be}~ x\%,\\\\~~~~~72 \cdot x \% = 9\\\\\\\implies 72\cdot \dfrac{x}{100} = 9\\\\\\\implies x = \dfrac{9 \times 100}{72}\\\\\\\implies x = \dfrac{100}{8}\\\\\\\implies x = \dfrac{25}2\\\\\\\implies x = 12 \dfrac 12\\\\\\\text{Hence 9 is}~ 12\dfrac 12\% ~ \text{of}~ 72$

4 0

2 years ago

Use De Moivre’s Theorem to compute the following: <img src="https://tex.z-dn.net/?f=%5B3%28cos27%2Bisin27%29%7D%5E5" id="TexForm

zhannawk [14.2K]

Hello:
<span>Use De Moivre’s Theorem :
</span>(3(cos27 +isin27)^5 = 3^5( cos(27 × 5) +isin(27 × 5))
= 3^5 ( cos(135)+i sin(135))
= 3^5(-√2/2+i √2/2)
because : cos(135) = -√2/2 and sin(135) = √2/2
(3(cos27 +isin27)^5 = (- 3^5√2/2)+ i ( 3^5√2/2) ...(form : a+ib when
a= (- 3^5√2/2) and b = ( 3^5√2/2)

4 0

3 years ago

Someone please help me ! Its past due and Ive been busy.. D:

oee [108]

Answer:

It's okay the first answer is right, $0.15

The store makes $4.20 off the rope

Step-by-step explanation:

4 0

3 years ago