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3 years ago

Can SOMEONE PLZ HELPP

Mathematics

1 answer:

slava [35]3 years ago

5 0

Answer:

-4

Step-by-step explanation:

What I would do to make it easier is to put them into exponential form. I would do 3 since goes with 1/9,81, and 27.

3^-2a-2=3^4a+4*3^6-3a

Now we can treat it like a normal equation

-2a-2=3^4a+4+6-2a

-2a-2=a+10

-3a=12

a=-4

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$\bold{2.\quad \text{Vertex}:(2,1)\qquad \text{Focus}:\bigg(\dfrac{9}{4},1\bigg)\qquad \text{Directrix}:y=\dfrac{7}{4}}$

<u>Step-by-step explanation:</u>

The vertex form of a parabola is y = a(x - h)² + k or x = a(y - k)² + h

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1) y = -2(x - 4)² - 1 → a = -2 (h, k) = (4, -1)

$a=\dfrac{1}{4p}\quad \rightarrow \quad -2=\dfrac{1}{4p}\quad \rightarrow \quad p=-\dfrac{1}{8}\\\\\text{Focus = Vertex + p}\\\\.\qquad = \dfrac{-8}{8}+\dfrac{-1}{8}\\\\.\qquad =-\dfrac{9}{8}\qquad \rightarrow \qquad \text{Focus}=\bigg(4,-\dfrac{9}{8}\bigg)\\\\\\\text{Directrix: y=Vertex - p}\\\\.\qquad \qquad y=\dfrac{-8}{8}-\dfrac{-1}{8}\\\\.\qquad \qquad y=-\dfrac{7}{8}$

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2) x = (y - 1)² + 2 → a = 1 (h, k) = (2, 1)

$a=\dfrac{1}{4p}\quad \rightarrow \quad 1=\dfrac{1}{4p}\quad \rightarrow \quad p=-\dfrac{1}{4}\\\\\text{Focus = Vertex + p}\\\\.\qquad = \dfrac{8}{4}+\dfrac{1}{4}\\\\.\qquad =\dfrac{9}{4}\qquad \rightarrow \qquad \text{Focus}=\bigg(\dfrac{9}{4},1\bigg)\\\\\\\text{Directrix: x=Vertex - p}\\\\.\qquad \qquad x=\dfrac{8}{4}-\dfrac{1}{4}\\\\.\qquad \qquad x=\dfrac{7}{4}$

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Step-by-step explanation:

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x² + 12x = 40

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x² + 12x + 36 = 40 +36

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