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3 years ago

Help..? Pleaseee , it has to do with the Pythagorean Theorem. But I have no idea how to do it

Mathematics

1 answer:

Rudiy273 years ago

7 0

Pythagorean Theorem is

a ²+ b ² = c ²

a and b are the shorter sides, while c is the hypotenuse, or longest side. Let’s say the side we are looking for is “b”.

Let’s first rearrange the equation, then sub in.

a ²+ b ² = c ²
b ² = c ²- a ²
b = √ (c ²- a ²)
b = √(17 ²- 15 ²)
b = √(289-225)
b = √ 64
b = 8

You might be interested in

F= 8/5 (c) + 40 when c=5

Molodets [167]

Answer:

F = 48

Step-by-step explanation:

F= 8/5 (c) + 40

Let c=5

F = 8/5 * 5 +40

= 8 + 40

= 48

6 0

3 years ago

Read 2 more answers

There are 84 boys in the 6th grade class. If boys make up 30% of the 6th graders, how many students are in this whole 6th grade

koban [17]

<h3>Answer: 280</h3>

Work Shown:

x = number of students in the 6th grade class

30% = 30/100 = 0.30

30% of x = 0.30x this is equal to 84 since "30% of the 6th graders are boys (and there are 84 boys in sixth grade)", so we say 0.30x = 84

Divide both sides by 0.30 to isolate x

0.30x = 84

0.30x/0.30 = 84/0.30

x = 280

So there are 280 students overall in the 6th grade class.

7 0

3 years ago

Read 2 more answers

What is the surface area of this prism? A. 976 cm2 B. 960 cm2 C. 488 cm2 D. 736 cm2

Vikki [24]

Answer:

The answer is C, 488 cm2

Step-by-step explanation:

5 0

3 years ago

The final cost of a sale item is determined by multiplying the price on the tag by 75%.which best describes the function that re

AnnZ [28]

Answer:

4V = 3U

Step-by-step explanation:

The final cost of a sale item is determined by multiplying the price on the tag by 75%.

Let us assume that the final cost of the sale item is V and the price on the tag is given by U.

Then the equation that best describes the function that represents the situation is $V = \frac{75U}{100} =\frac{3U}{4}$

⇒ 4V = 3U (Answer)

3 0

3 years ago

Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

7 0

2 years ago