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ddd [48]
3 years ago
10

The median of the values 3.4, 4.7, 1.9, 7.6, and 6.5

Mathematics
1 answer:
vladimir2022 [97]3 years ago
5 0

Answer:

4.7

Step-by-step explanation:

the median is the middle number in a set of numbers so first we need to put them in order

1.9 3.4 [4.7] 6.5 7.6

this one is easy since we have an odd number of digits

the answer is 4.7

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How many times dose 10 go into 450
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Answer:

10 go into 450 45 times

Step-by-step explanation:

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1. William earns $134,644.80 per year, and has his federal taxes withheld from each weekly check. In addition, a total of $53.60
SashulF [63]
I only have the answer for 3 and i believe it is 20,090

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3 years ago
Find the rate of change: Mike can bike 3 miles in an hour. What is the speed at which mike can bike?
masya89 [10]
Rate  of  change=<span><span>change  in  y divided by </span><span>change  in  <span>x
y= 3,6,9
x= 1,2,3
The numbers chosen above are because if mike travels 3 miles in one hours then he can travel 6 miles in two hours and 9 miles in 3 hours. 
Change in y = 3
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3 / 1 = 3
So, the rate of change is 3.</span></span></span>
3 0
3 years ago
Use the model to solve for x
laila [671]

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A) no solution

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<em>2. This </em><em>equation does not provide enough facts</em><em> to be able to solve this</em>

<em>3. It is a </em><em>trick question</em><em> </em><em>don't fall for it</em>

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5 0
4 years ago
Read 2 more answers
URGENT: If θ is a second-quadrant angle and cosθ = -2/3, then tanθ = _____.
dangina [55]

In the second quadrant, both cos and tan are negative while only sin is positive.

To find tan, we will use the following property below:

\large \boxed{ {tan}^{2}  \theta  =  {sec}^{2}   \theta - 1}

Sec is the reciprocal of cos. If cos is a/b then sec is b/a. Since cos is 2/3 then sec is 3/2

\large{ {tan}^{2}  \theta =  {( -  \frac{3}{2}) }^{2}  - 1} \\   \large{ {tan}^{2}  \theta =   \frac{9}{4}  - 1} \\   \large{ {tan}^{2}  \theta = \frac{9}{4}   -  \frac{4}{4} \longrightarrow  \frac{5}{4}  } \\  \large{tan \theta =  \frac{ \sqrt{5} }{ \sqrt{4} } } \\  \large \boxed{tan \theta =  \frac{ \sqrt{5} }{2} }

Since tan is negative in the second quadrant. Hence,

\large{ \cancel{ tan \theta  =  \frac{ \sqrt{5} }{2} } \longrightarrow \boxed{tan \theta =  -  \frac{ \sqrt{5} }{2} }}

Answer

  • tan = -√5/2
3 0
3 years ago
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