Practice and problem lesson 25

Inequality n < -5 HELPPP ASAPPP

ale4655 [162]

Answer:

please give me a brainless 0

Inequality :

α1+(n−1)a−(⌊n÷m⌋×(a−b))≥x

The following is as far as I get:

α1+(n−1)a−(⌊n÷m⌋×(a−b))≥x

(n−1)a−(⌊n÷m⌋×(a−b))≥x−α1

n−1−(⌊n÷m⌋×(a−b))≥x−α1a

n−(⌊n÷m⌋×(a−b))≥x−α1a + 1

Step-by-step explanation:

3 0

3 years ago

Round 5.951 to the place value of the underlined digit ( underlined digit is 9)

mr Goodwill [35]

Answer:

A.) 6.0

Step-by-step explanation:

I dont explain very well, but..

if the next number is above or it is 5, then u round up

5 0

3 years ago

The annual energy consumption of the town where Camilla lives in creases at a rate that is onal at any time to the energy consum

boyakko [2]

Answer:

6.575 trillion BTUs

Step-by-step explanation:

Let represent the annual energy consumption of the town as E

The rate of annual energy consumption * energy consumption at time past

dE/dt * E

dE/dt =K

k = the proportionality constant

c= the integration constant

(dE/dt=) kdt

lnE = kt + c

E(t) = e^kt+c ⇒ e^c e^kt e^c is a constant, and e^c = E₀

E(t) = E₀ e^kt

The initial consumption of energy is E(0)=4.4TBTU

set t = 0 then

4.4 = E₀ e⇒ E₀ (1)

E₀ = 4.4

E (t) = 4.4e^kt

The consumption after 5 years is t = 5, e(5) = 5.5TBTU

so,

E(5) = 5.5 = 4.4e^k(5)

e^5k = 5/4

We now take the log 5kln = ln(5/4)

5k(1) = ln(5/4)

k = 1/5 ln(5/4) = 0.04463

We find the town's annual energy consumption, after 9 years

we set t=9

E(9) = 4.4e^0.04463(9)

= 4.4(1.494301) = 6.5749TBTUs

Therefore the annual energy consumption of the town after 9 years is

= 6.575 trillion BTUs

3 0

3 years ago

Use Newton's Method to approximate the zero(s) of the function. Continue the iterations until two successive approximations diff

liubo4ka [24]

Answer:

There is only one real zero and it is located at x = 1.359

Step-by-step explanation:

After the 4th iteration the solution was repeating the first 3 decimal places. The formula for Newton's Method is

$x_{n}-\frac{f(x_{n}) }{f'(x_{n}) }$

If our function is

$f(x)=x^5+x-6$

then the first derivative is

$f'(x)=5x^4+1$

I graphed this on my calculator to see where the zero(s) looked like they might be, and saw there was only one real one, somewhere between 1 and 2. I started with my first guess being x = 1.

When I plugged in a 1 for x, I got a zero of 5/3.

Plugging in 5/3 and completing the process again gave me 997/687

Plugging in 997/687 and completing the process again gave me 1.36976

Plugging in 1.36976 and completing the process again gave me 1.359454

Plugging in 1.359454 and completing the process again gave me 1.359304

Since we are looking for accuracy to 3 decimal places, there was no need to go further.

Checking the zeros on the calculator graphing program gave me a zero of 1.3593041 which is exactly the same as my 5th iteration!

Newton's Method is absolutely amazing!!!

5 0

3 years ago

Which of the following is a linear function

Feliz [49]

Answer:

f(x)=5x-6

Step-by-step explanation:

When I entered this in Desmos it crossed through the line crossed through the x and y axis which makes this equation a linear function.

3 0

3 years ago

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