Question

One positive number exceeds three times another positive number by 5. The product of the two numbers is 68. Find the number

Answer 1

Answer:12

Step-by-step explanation:

Let the numbers be a and b

a-3b=5 ........equation (1)

There product is :

ab=68 ..........equation (2)

From equation (1)

a-3b=5

Make a the subject of the formula

a=5+3b. ........equation (3)

Substitute equation (3) into equation (2)

(5+3b)b=68

3(b^2)+3b-68=0

The product is -204b^2(17 and -12)

(b+17)(b-12)=0

b=-17 or b=12

So the number is 12