If an object accelerates from rest, with a constant acceleration of 4.4 m/s2, what will its velocity be after 28s?

Physics

1 answer:

Norma-Jean [14]3 years ago

6 0

Answer:

123.2 m/s after 28s

Explanation:

Vi= 0 m/s

a= 4.4 m/s^2

t=28s

Vf after 28s

To find Vf use your kinematics formula Vf=Vi+at

Vi is Zero so it gets removed and the equation becomes

Vf=at

Simply Plug and Solve

Vf= 4.4(28)

Vf=123.2 m/s after 28s

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