Part C

Two parallel-plate capacitors have the same plate area, but the plate gap in capacitor 1 is twice as big as capacitor 2. If capa

-BARSIC- [3]

Answer:

Capacitance of the second capacitor = 2C

Explanation:

$\texttt{Capacitance, C}=\frac{\varepsilon_0A}{d}$

Where A is the area, d is the gap between plates and ε₀ is the dielectric constant.

Let C₁ be the capacitance of first capacitor with area A₁ and gap between plates d₁.

We have

$\texttt{Capacitance, C}_1=\frac{\varepsilon_0A_1}{d_1}=C$

Similarly for capacitor 2

$\texttt{Capacitance, C}_2=\frac{\varepsilon_0A_2}{d_2}=\frac{\varepsilon_0A_1}{\frac{d_1}{2}}=2\times \frac{\varepsilon_0A_1}{d_1}=2C$

Capacitance of the second capacitor = 2C

6 0

3 years ago

Calculate the binding energy per nucleon of the helium nucleus 52he. express your answer in millions of electron volts to four s

Vitek1552 [10]

The main formula is given by Eb/nucleon = Eb/ mass of nucleid
as for 52He, the mass is 5
so by applying Einstein's formula Eb=DmC², Eb=binding energy
52He-----------> 2 x 11p + 3 x10n is the equation bilan
so Dm=2 mp + (5-2)mn-mnucleus, mp=mass of proton=1.67 10^-27 kg
mn=mass of neutron=1.67 10^-27 kg
 m nucleus= 5
Dm= 2x1.67 10^-27 kg+ 3x1.67 10^-27 kg-5= - 4.9 J
Eb= - 4.9 J x c²= -4.9 x 9 .10^16= - 45 10^16 J
so the answer is Eb /nucleon = Eb/5= -9.10^16 J, but 1eV=1.6 . 10^-19 J
so -9.10^16 J/ 1.6 10^-19= -5.625 10^35 eV

the final answer is Eb /nucleon = -5.625 x10^35 eV

8 0

3 years ago

The musical tone a piano has a frequency of 346HZ and a wavelength of 1.3 M what is the speed of the sound

prohojiy [21]

Answer:

v= 449.8 m/s

Explanation:

Given data

Frequency= 346Hz

Wave length= 1.4m

The expression below is used to find the speed

$v= f \lambda\\\\$

substitute

$v= 346*1.3\\\\v= 449.8 m/s$

Hence the speed is v= 449.8 m/s

5 0

3 years ago

Alex, parked by the side of an east-west road, is watching car P, which is moving in a westerly direction. Barbara, driving east

Alexxandr [17]

Answer:

$v_{PB} = 130\ km/h$

Explanation:

Since, Alex is at rest. Therefore, the speed measured by him will be the absolute speed of car P. Therefore, taking easterly direction as positive:

$Absolute\ Velocity\ of\ Car\ P = v_{P} = -78\ km/h$

And the absolute velocity of Barbara's Car is given as: $Absolute\ Velocity\ of\ Barbara's\ Car = v_{B} = 52\ km/h$

Now, for the velocity of Car p with respect to the velocity of Barbara's Car can be given s follows:

$Velocity\ of\ Car\ P\ measured\ by\ Barbara = v_{PB} = v_{B}-v_{P}\\\\v_{PB} = 52\ km/h-(-78\ km/h)$

$v_{PB} = 130\ km/h$

6 0

2 years ago

What safety measures would you suggest to protect from harmful waves

AfilCa [17]

Answer:

If you're talking about the sun than:

Time, Distance and Shielding Time, distance, and shielding actions minimize your exposure to radiation in much the same way as they would to protect you against overexposure to the sun:

If you're talking about the ocean than:

Water safety precautions for teens and young adults:

Never go into the water if you can’t swim.

If you can’t swim, learn. Any age can receive swimming lessons.

Always wear a life jacket while boating or taking part in boating activities such as tubing or skiing.

Never swim alone or in an unsupervised area.

Know your swimming strength.

Don’t rough house around water. Never push, jump on or hang on to others in or around water.

Never drink alcohol while taking part in water or boating activities. Alcohol affects your motor skills therefore making it harder to swim, float, keep balance or drive.

Explanation:

4 0

3 years ago