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eimsori [14]
3 years ago
12

A certain amount of oxygen gas in a container of volume 1.5 x 10^-2 m^3 has a temperature of 302 K and at a pressure of 2.5 x 10

^5 Pa. After some of the oxygen gas is allowed to escape from the container, the pressure drops to 1.2 x 10^5 Pa. How much (in SI unit) the gas has escaped?​
Physics
1 answer:
Bogdan [553]3 years ago
8 0

Answer:

Ve = 0.01625 [m³]

Explanation:

This type of problem can be solved by the following expression.

P_{i}*V_{i}*T_{o}=P_{o}*V_{o}*T_{i}

where_

Pi = Initial pressure = 2.5 x 10⁵ [Pa]

Vi = initial volume = 1.5 x 10⁻² [m³]

To = final temperature = 302 [K]

Po = final pressure = 1.2 x 10⁵ [Pa]

Vo = final volume [m³]

Ti = initial temperature = 302 [K]

Now the key to solving this problem is to make it clear that the temperature remains constant throughout the process. That is, it does not change.

2.5*10^{5}*1.5*10^{-2} *302 = 1.2*10^{5}*V_{o}*302\\1132500=36240000*V_{o}\\V_{o}=0.03125 [m^{3} ]

But this calculated volume corresponds to the volume of the tank, now by means of the difference between the initial volume and the final volume we can calculate the volume of gas that escaped.

V_{e}=0.03125-0.015\\V_{e}=0.01625 [m^{3} ]

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The density is 81.4 g/m3. Before you start plugging numbers into the density formula (D=M/V), you should convert 104 kg to grams, which ends up being 104,000 grams. Then you can plug in the 104,000 grams and 1,278 m3 into the formula. When you divide the mass by the volume, you get a really long decimal, which you can round to 81.4 g/m3, or whatever place your teacher wants you to round to.
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2 years ago
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Answer:

θ = 41.8º

Explanation:

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Answer:

0.0133A

Explanation:

Since we have two sections, for the Inductor region there would be a current i_1. In the case of resistance 2, it will cross a current i_2

Defined this we proceed to obtain our equations,

For i_1,

\frac{di_1}{dt}+i_1R_1 = V

I_1 = \frac{V}{R_1} (1-e^{-\frac{R_1t}{L}})

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Replacing in the current for t= 0.4m/s

i=\frac{1}{360}+\frac{1}{95}(1-e^{-\frac{95*0.4}{1.5*10^{-2}}})

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d

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