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3 years ago

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A certain amount of oxygen gas in a container of volume 1.5 x 10^-2 m^3 has a temperature of 302 K and at a pressure of 2.5 x 10

^5 Pa. After some of the oxygen gas is allowed to escape from the container, the pressure drops to 1.2 x 10^5 Pa. How much (in SI unit) the gas has escaped?

1 answer:

Bogdan [553]3 years ago

8 0

Answer:

Ve = 0.01625 [m³]

Explanation:

This type of problem can be solved by the following expression.

$P_{i}*V_{i}*T_{o}=P_{o}*V_{o}*T_{i}$

where_

Pi = Initial pressure = 2.5 x 10⁵ [Pa]

Vi = initial volume = 1.5 x 10⁻² [m³]

To = final temperature = 302 [K]

Po = final pressure = 1.2 x 10⁵ [Pa]

Vo = final volume [m³]

Ti = initial temperature = 302 [K]

Now the key to solving this problem is to make it clear that the temperature remains constant throughout the process. That is, it does not change.

$2.5*10^{5}*1.5*10^{-2} *302 = 1.2*10^{5}*V_{o}*302\\1132500=36240000*V_{o}\\V_{o}=0.03125 [m^{3} ]$

But this calculated volume corresponds to the volume of the tank, now by means of the difference between the initial volume and the final volume we can calculate the volume of gas that escaped.

$V_{e}=0.03125-0.015\\V_{e}=0.01625 [m^{3} ]$

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viktelen [127]

Answer:

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Explanation:

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In case of a circular loop, the directions of magnetic field and the line element $d\vec l$ , both are along the tangent of the loop at that point, therefore, $\vec B\cdot d\vec l = B\ dl$ .

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For the first wire, passing through the origin:

Consider an Amperian loop of radius 3.510 m, concentric with the axis of the wire, such that it passes through the point where magnetic field is to be found, therefore, $r_1 = 3.510\ m.$

The magnetic field at the given point due to this wire is given by:

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For the first wire, passing through the y-axis:

Consider an Amperian loop of radius (3.510+1.8) m = 5.310 m, concentric with the axis of the wire, such that it passes through the point where magnetic field is to be found, therefore, $r_2 = 5.310\ m.$

The magnetic field at the given point due to this wire is given by:

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The directions of current in both the wires are opposite therefore, the directions of the magnetic field due to both the wires are also opposite to that of each other.

Thus, the net magnetic field at $r_r=-3.510\ m$ is given by

$B=B_1-B_2 = 1.42\times 10^{-5}-1.88\times 10^{-6}=1.232\times 10^{-5}\ T.$

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