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3 years ago

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A certain amount of oxygen gas in a container of volume 1.5 x 10^-2 m^3 has a temperature of 302 K and at a pressure of 2.5 x 10

^5 Pa. After some of the oxygen gas is allowed to escape from the container, the pressure drops to 1.2 x 10^5 Pa. How much (in SI unit) the gas has escaped?

1 answer:

Bogdan [553]3 years ago

8 0

Answer:

Ve = 0.01625 [m³]

Explanation:

This type of problem can be solved by the following expression.

$P_{i}*V_{i}*T_{o}=P_{o}*V_{o}*T_{i}$

where_

Pi = Initial pressure = 2.5 x 10⁵ [Pa]

Vi = initial volume = 1.5 x 10⁻² [m³]

To = final temperature = 302 [K]

Po = final pressure = 1.2 x 10⁵ [Pa]

Vo = final volume [m³]

Ti = initial temperature = 302 [K]

Now the key to solving this problem is to make it clear that the temperature remains constant throughout the process. That is, it does not change.

$2.5*10^{5}*1.5*10^{-2} *302 = 1.2*10^{5}*V_{o}*302\\1132500=36240000*V_{o}\\V_{o}=0.03125 [m^{3} ]$

But this calculated volume corresponds to the volume of the tank, now by means of the difference between the initial volume and the final volume we can calculate the volume of gas that escaped.

$V_{e}=0.03125-0.015\\V_{e}=0.01625 [m^{3} ]$

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Answer:

Explanation:

Given

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third Particle which charge +q must be placed left of $2.5\mu C$ because it will repel the q charge while $-3.5\mu C$ will attract it

suppose it is placed at a distance of x m

$F_{1q}=\frac{kq(2.5)}{x^2}$

$F_{2q}=\frac{kq(-3.5)}{(0.6+x)^2}$

$F_{1q}+F_{2q}=0$

$\frac{kq(2.5)}{x^2}+\frac{kq(-3.5)}{(0.6+x)^2}=0$

$\frac{kq(2.5)}{x^2}=\frac{kq(3.5)}{(0.6+x)^2}$

$\frac{0.6+x}{x}=(\frac{3.5}{2.5})^{0.5}$

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Answer:

A) if each astronaut breathes about 500 cm³, the total volume of air breathed in a year is 14716.8m³.

B) The Diameter of this spherical space station should be 30.4m

Explanation:

The breathing frequency (according to Rochester encyclopedia) is about 12-16 breath per minute. if we take the mean value (14 breath per minute), we can estimate the total breaths of a person along a year:

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If we multiply this for the number of people in the station and the volume each breath needs, we obtain the volume breathed in a year.

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So the diameter is:

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The average velocity or displacement of a particle for the first time interval is <u>Δs / Δt = 6 cm/s.</u>

Solution:

As we know that displacement is calculated in centimeters and the unit of time is second.

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If you need to learn more about displacement click here:

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