A certain amount of oxygen gas in a container of volume 1.5 x 10^-2 m^3 has a temperature of 302 K and at a pressure of 2.5 x 10
1 answer:
Answer:
Ve = 0.01625 [m³]
Explanation:
This type of problem can be solved by the following expression.
where_
Pi = Initial pressure = 2.5 x 10⁵ [Pa]
Vi = initial volume = 1.5 x 10⁻² [m³]
To = final temperature = 302 [K]
Po = final pressure = 1.2 x 10⁵ [Pa]
Vo = final volume [m³]
Ti = initial temperature = 302 [K]
Now the key to solving this problem is to make it clear that the temperature remains constant throughout the process. That is, it does not change.
But this calculated volume corresponds to the volume of the tank, now by means of the difference between the initial volume and the final volume we can calculate the volume of gas that escaped.
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Answer:
Second order line appears at 43.33° Bragg angle.
Explanation:
When there is a scattering of x- rays from the crystal lattice and interference occurs, this is known as Bragg's law.
The Bragg's diffraction equation is :
.....(1)
Here n is order of constructive interference, λ is wavelength of x-ray beam, d is the inter spacing distance of lattice and θ is the Bragg's angle or scattering angle.
Given :
Wavelength, λ = 1.4 x 10⁻¹⁰ m
Bragg's angle, θ = 20°
Order of constructive interference, n =1
Substitute these value in equation (1).
d = 2.04 x 10⁻¹⁰ m
For second order constructive interference, let the Bragg's angle be θ₁.
Substitute 2 for n, 2.04 x 10⁻¹⁰ m for d and 1.4 x 10⁻¹⁰ m for λ in equation (1).
<em>θ₁ </em>= 43.33°