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Savatey [412]
3 years ago
12

⚠️NEED HELP ASAP ⚠️The following polygons are similar. Solve for x.

Mathematics
1 answer:
Nikolay [14]3 years ago
6 0
G it’s 6 answer hope it helps sorry if I wrong
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Determine the exact solution to the following in radians.
Sloan [31]
3sinx+1=sinx
2sinx+1=0
2sinx=-1
sinx=-1/2
x=sin^-1 (1/2) = 30 = \pi/6 (when finding the inverse, always take the positive value, ignore the negative sign)
x is therefore negative in 3rd and 4th quadrant
Therefore values of x are:
180+30=210 = 7\pi/6
360-3=330 = 11\pi/6
3 0
3 years ago
At 1:00 am, the temperature in Finland was -8⁰F. By noon, the temperature was 25⁰F. What was the change in temperature, in degre
Margarita [4]
The temperature went up by 33° fahrenheit because -8+8=0 and 0+25= 25 so 8+25=33
6 0
2 years ago
In the number 668 the 6 in the hundreds place is _ the value of the 6 in the tens place
mihalych1998 [28]
6 in the hundreds place = 600
6 in the tens place =60
4 0
3 years ago
Y varies directly with x and y = 12 when x =5 what is the value of y when x = 8
torisob [31]
Y and x are directly proportional, as stated by hypothesis. Let's use the rule of three to find y when x = 8.

x=5 --> y=12
x=8 --> y=?

? = (8*12)/5 = 96/5 = 19.2

So y directly varies with x, and y=12 when x = 5, then y=19.2 when x=8.

Hope this Helps! :D
3 0
3 years ago
100 points! Please help asap! Look at the picture attached. My teacher said that both 1 and 2 are neither can someone explain wh
Neko [114]

Answer:

Your teacher is right, there is not enough info

Step-by-step explanation:

<h3>Question 1</h3>

We can see that RS is divided by half

The PQ is not indicated as perpendicular to RS or RQ is not indicates same as QS

So P is not on the perpendicular bisector of RS

<h3>Question 2</h3>

We can see that PD⊥DE and PF⊥FE

There is no indication that PD = PF or ∠DEP ≅ FEP

So PE is not the angle bisector of ∠DEF

6 0
3 years ago
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