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Harman [31]
3 years ago
6

I NEED HELP PLS i don’t understand exactly how to do this :/

Mathematics
1 answer:
Sholpan [36]3 years ago
4 0

Answer:

I assume AC = 49.89 since the number is cut off

Step-by-step explanation:

tangent(degree) = opposite / adjacent

To find AC, you can set up tan(29) = AC / CB

tan(29) = AC / 90 (the picture is cutted off, so I assume....)

90*tan(29) = AC

You might be interested in
Given p(x) = x+7/3<br> if p(x) = 13, find x.
Shtirlitz [24]

Answer:

x = \frac{32}{3}

Step-by-step explanation:

We know that p(x) = 13. Thus, substitute 13 for the "p(x)" in the equation. Then, isolate x by subtracting both sides by \frac{7}{3}:

p(x) = x + \frac{7}{3}\\13 = x + \frac{7}{3} \\13 - \frac{7}{3} = x \\\frac{39}{3}- \frac{7}{3} = x \\\frac{32}{3} = x

Thus, x = \frac{32}{3}.

3 0
3 years ago
For her exercise today, Keiko plans to both run and swim. Let r be the number of laps she runs and let s be the number of laps s
DerKrebs [107]

Answer:

5r + 3s ≥ 30

Step-by-step explanation:

We know Keiko wants to do exercise at least 30 minutes a day, and she wants ideally to mix up the activities, by combining running and swimming into her schedule.

Since each lap she runs takes 5 minutes and each lap she swims takes 3 minutes, these will be the left side of the inequality:

5r + 3s

She wants to exercise at least 30 minutes a day, so...

5r + 3s ≥ 30

she could do 3 laps of running and 5 laps of swimming for example.

6 0
3 years ago
ASAP I NEED HELP <br> four 28s in lowest terms​
Margaret [11]

1/7 is the answer. 4/28 = 1/7 but in the lowest term

5 0
3 years ago
Find the midpoint of the segment with the given endpoints. (9.-9) and (2.-10)​
kondor19780726 [428]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{(5.5 \: , \: -  9.5)}}}}}

Step-by-step explanation:

Let the points be A and B

Let A ( 9 , -9 ) be ( x₁ , y₁ ) and B ( 2 , - 10 ) be ( x₂ , y₂ )

<u>Finding</u><u> </u><u>the</u><u> </u><u>midpoi</u><u>nt</u>

\boxed{ \sf{midpoint = ( \frac{x1 + x2}{2} , \frac{y1 + y2}{2} }}

\longrightarrow{ \sf{midpoint = ( \frac{9 + 2}{2} , \:  \frac{ - 9  + ( - 10)}{2}}} )

\longrightarrow{ \sf {midpoint = ( \frac{11}{2} \: , \:  \frac{ - 9 - 10}{2}})}

\longrightarrow{  \sf{midpoint = (5.5 \: , \:  \frac{ - 19}{2}}} )

\longrightarrow{ \sf{midpoint = (5.5 \: , - 9.5}})

Hope I helped!

Best regards! :D

5 0
3 years ago
All the info is in the pictures
Hunter-Best [27]
Bearing in mind that an absolute value expression is in effect a piece-wise function with two cases, thus

\bf |-n|=&#10;\begin{cases}&#10;+(-n)\\&#10;-(-n)&#10;\end{cases}\implies &#10;\begin{cases}&#10;-n\\&#10;n&#10;\end{cases}&#10;\\\\\\&#10;n|-n|=2n\implies &#10;\begin{cases}&#10;n-n=2n\implies 0=2n\implies &0=n\\&#10;n+n=2n\implies 2n=2n\impliedby &inconsistent&#10;\end{cases}
6 0
3 years ago
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