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Vsevolod [243]
3 years ago
8

A bucket holds b liters of water. But a jar holds 8 fewer liters than the bucket. How many times can the bucket hold than the ja

r? Thanks for your help!
Mathematics
1 answer:
kykrilka [37]3 years ago
8 0

Answer:

b / (b - 8)

Step-by-step explanation:

Given that :

Litres of water held by bucket = b

Jar holds 8 litres fewer than bucket; hence, litres held by jar = b - 8

The number of times bucket can hold than jar is :

Litres held by bucket / litres held by jar

b / (b - 8)

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What is the range of the relation?​
tia_tia [17]
The correct answer is (-2,1,2,8)

The range are the y- values

The explanation:

The range is the set of all second elements of ordered pairs (y-coordinates). Only the elements "used" by the relation or function constitute the range.

Hope this helped you :D
7 0
3 years ago
The ages of the Oscar-winners for best actor and actress for the years 1970 through 1990 are given below: Women: 34, 34,26,37,42
Artemon [7]

Answer:

See explanation below.

Step-by-step explanation:

Numerical way

We can calculate the mean and the standard deviation from a sample with the following formulas:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

s= \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}

We have the following dataset for women: 34,34,26,37,42,41,35,31,41,33,30,74,33,49,38,61,21,41,26,80,72

And the mean and deviation are:

\bar X_F = 41.857

s_F = 16.399

We can calculate the median ordering the data like this:

21,26,26,30,31,33,33,34,34,35,37,38,41,41,41,42,49,61,72,74,80

And the median would be on the 11 position of the data ordered, for this case is:

median_F = 37

Minimum_F = 21 , Maximum_F = 80

And the range is given by: Range_F = 80-21=59

We can also calculate the coefficient of variation given by:

\hat{CV} =\frac{s}{\bar X} = \frac{16.399}{41.857}=0.392

We have the following dataset for men:

43, 40,48,48,56,38,60,32,40,42,37,76,39,55,45,35,61,33,51,32,42

And the mean and deviation are:

\bar X_M = 45.381

s_M = 11.218

We can calculate the median ordering the data like this:

32, 32,33,35,37,38,39,40,40,42,42,43,45,48,48,51,55,56,60,61,76

And the median would be on the 11 position of the data ordered, for this case is:

median_M = 42

Minimum_M = 32 , Maximum_F = 76

And the range is given by: Range_M = 76-32=44

We can also calculate the coefficient of variation given by:

\hat{CV} =\frac{s}{\bar X} = \frac{11.218}{45.381}=0.247

We se that the mean for the male groups is higher than the mean for female group. The deviation is higher for the female group comapred to the male group. We have more variation for the female group as we can see on the range and the coeffcient of variation.

Graph

We can see the histograms for each group on the figures attached.

As we can see the histogram for males is skewed to the right with the median lower than the mean.

By the other hand the histogram for the female group seems to be skewed to the right also but with missing values on the interval 50-60, for this reason we have more variation compared to the male group.

7 0
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The box plots below show the average gas mileage, in miles per gallon, of the cars sold at a dealership in June and in
LekaFEV [45]

Answer:

The interquartile range for December should be 21 minus 18 = 3.

Step-by-step explanation:

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Answer:

y = 4x - 1

Step-by-step explanation:

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The weather man announced that there was a temperature drop Of 8 degrees from yesterday to today. How would this be represented
uysha [10]

that will be not so shore of what will you think but if you used a thermometer and you see how it will change

8 0
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