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2 years ago

The first two angles in a triangle are 90 degrees and 50 degrees. What does the third angle have to be?

Mathematics

1 answer:

s2008m [1.1K]2 years ago

5 0

Answer:

B) 40 degrees

Step-by-step explanation:

90 + 50 = 140

Each triangle have 180 °

180 - 140 = 40

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If r = 11 units and h = 8 units, then what is the volume of the cylinder shown above?

zhenek [66]

Answer:

968π ≈ 3041 . . . cubic units

Step-by-step explanation:

The usual formula for the volume of a cylinder is ...

V = πr²h

For your given dimensions, the volume is found by putting the values into the formula and doing the arithmetic.

V = π(11²)(8) = 968π . . . . cubic units

V ≈ 3041 cubic units

6 0

3 years ago

Omar, Hala and Lujain got paid a total of $240 for cleaning neighborhood cars. They split the money in the ratio of 5: 9: 10. Wh

Blababa [14]

Answer:

i dont know

Step-by-step explanation:

i dont know

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2 years ago

If you solve the equation for ax+by/c=d for x, what would you get?

Xelga [282]

<u>Answer:</u>

x=d/a - by/ac

<u>Steps:</u>

ax+by/c=d

(cax+by)/c=d

cax+by=cd

cax=cd-by

x=(cd-by)/ca

x=cd/ca - by/ca

x=d/a - by/ac

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2 years ago

raja bought 500 hens among them 75 were died by cold . he sold the remaining hens at the rate of rs 120 per hen and made a profi

lina2011 [118]

CP hens remianing = 5000

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2 years ago

g A researcher wants to construct a 95% confidence interval for the proportion of children aged 8-10 living in Atlanta who own a

Helga [31]

Answer:

The sample size needed is 2401.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error of the interval is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

Estimate the sample size needed if no estimate of p is available so that the confidence interval will have a margin of error of 0.02.

We have to find n, for which M = 0.02.

There is no estimate of p available, so we use $\pi = 0.5$

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.02 = 1.96\sqrt{\frac{0.5*0.5}{n}}$

$0.02\sqrt{n} = 1.96*0.5$

$\sqrt{n} = \frac{1.96*0.5}{0.02}$

$(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.02})^{2}$

$n = 2401$

The sample size needed is 2401.

7 0

2 years ago

Read 2 more answers