Joel can either work 2 days for 11 hours each day or 4 days for 6 hours each day. He takes the bus for $2.25 each way. On days h
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Answer:
We have that
Step-by-step explanation:
We have just to replace n=10 on the general equation
Therefore:
Answer:
1. coefficient of variation(systolic) = 13.88%
2. coefficient of variation(diastolic) = 16.2%
3. The coefficients of variation for each data set are within 5 percentage points of each other Therefore the systolic measurements vary signifcantly less than the diastolic
Step-by-step explanation:
1. Mean of systolic = ( 117+126+158+96+157+122+116+134+127+122)÷10
= 127.5
Standard Deviation of systolic = (((117-127.5)^2 +(126-127.5)^2+(158-127.5)^2+ (96-127.5)^2 + (157-127.5)^2 + (122-127.5)^2 + (116-127.5)^2 +(134-127.5)^2 +(127-127.5)^2 +( 122-127.5)^2) ÷ 10)^(0.5)
SD = 17.7
coefficient of variation(systolic)
= Standard Deviation of systolic /mean of systolic
=
coefficient of variation(systolic) = 13.88%
2. Mean of diastolic = ( 80+77+76+51+90+89+60+64+72+83) ÷ 10
= 74.2
Standard Deviation of diastolic = (((80-74.2)^2 +(77-74.2)^2+(76-74.2)^2+ (51-74.2)^2 + (90-74.2)^2 + (89-74.2)^2 + (60-74.2)^2 +(64-74.2)^2 +(72-74.2)^2 +(83-74.2)^2) ÷ 10)^(0.5)
SD = 12
coefficient of variation(diastolic)
= Standard Deviation of diastolic /mean of diastolic
=
coefficient of variation(diastolic) = 16.2%
3. The coefficients of variation for each data set are within 5 percentage points of each other Therefore the systolic measurements vary signifcantly less than the diastolic