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Zanzabum
3 years ago
13

Why does the highest percent profit occur with the smallest annual interest rate?

Mathematics
1 answer:
anzhelika [568]3 years ago
4 0

Answer:

This is so because the higher the interest rate the lower the profit and the higher the total expenses and the percentage profit = (Profit/Expenses) × 100

Step-by-step explanation:

Question;

It is desired to find out the monthly percentage profit made to help decide the best loan option

Part A

Given that the monthly operating cost of the gym is 5,000 and the monthly sales is 7,500

Let 'I' represent the monthly interest paid on the loan, we have;

The percentage profit = Profit/(Total expenses) × 100

The total expenses = I + 5000

Profit = Sales - The total expenses

∴ Profit = 7,500 - (I + 5,000) = 2,500 - I

The percentage profit, P = (2,500 - I)/(5,000 + I) × 100

Therefore, as the interest rate becomes smaller, the numerator of the function for the percentage profit approaches its maximum value of 2,500 and the denominator approaches the minimum value of 5,000 and the percentage profit therefore, approaches the maximum value

Therefore;

The highest percentage profit occurs at the smallest interest rate.

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What is the area of rhombus ABCD? Enter your answer in the box. Do not round at any steps.
Mrac [35]

Answer:

Area of the rhombus ABCD = 16 square units

Step-by-step explanation:

Area of a rhombus = \frac{1}{2}(\text{Diagonal 1})(\text{Diagonal 2})

From the graph attached,

Diagonal 1 = Distance between the points A and C

Diagonal 2 = Distance between the points B and D

Length of a segment between (x₁, y₁) and (x₂, y₂) = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^2 }

Diagonal 1 (AC) = \sqrt{(4-0)^2+(-1+1)^2} = 4 units

Diagonal 2(BD) = \sqrt{(2-2)^2+(3+5)^2} = 8 units

Now area of the rhombus ABCD = \frac{1}{2}(\text{AC})(\text{BD})

                                                       = \frac{1}{2}\times 4\times 8

                                                       = 16 units²

Therefore, area of the given rhombus is 16 units².

5 0
3 years ago
Which graph represent bad a function of x
Dennis_Churaev [7]

Answer:

idk

Step-by-step explanation:

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8 0
3 years ago
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dmitriy555 [2]

Answer: Yes, Raoul is correct because the initial value, also known as the y-intercept of function A is 0 and function B is 3.

Step-by-step explanation: The initial value is when x=0.

3 0
2 years ago
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Find the smallest positive integer solution to the following system of congruences: x = 0 (mod 5) x = 8 (mod 11) The solution is
igomit [66]

Answer:

The smallest positive integer solution to the given system of congruences is 30.

Step-by-step explanation:

The given system of congruences is

x=0(mod5)

x=8(mod11)

where, m and n are positive integers.

It means, if the number divided by 5, then remainder is 0 and if the same number is divided by 11, then the remainder is 8. It can be defined as

x=5m

x=11n+8

5m\cong 11n+8

Now, we can say that m>n because m and n are positive integers.

For n=1,

5m=11(1)+8=19

5m=19

19 is not divisible by 5 so m is not an integer for n=1.

For n=2,

5m=11(2)+8

5m=30

m=6

The value of m is 6 and the value of n is 2. So the smallest positive integer solution to the given system of congruences is

x=5(6)=30

Therefore the smallest positive integer solution to the given system of congruences is 30.

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