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2 years ago

7

Can someone help me really please

1 answer:

JulsSmile [24]2 years ago

4 0

Answer:

26

Step-by-step explanation:

Let x represent the missing number

$8\frac{11}{15} = 7\frac{x}{15}$

Convert both fractions to improper fractions

$\frac{131}{15} = \frac{105 + x}{15}$

Cross multiply

$15(105 + x) = 15(131)$

$1,575 + 15x = 1,965$

Subtract both sides by 1,575

$15x = 1,965 - 1,575$

$15x = 390$

Divide both sides by 15

$x = \frac{390}{15}$

x = 26

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What is 4/5+1/4 ? In fraction form.

snow_lady [41]

To answer this question you must make a come factor between the 2 fractions I believe the easiest way to do this is multiply the denominator or bottom number by the other one so 4*5 and 5*4 and what you do to the denominator you must do to the numerator so you would have to do 4*4 and 4*5 for the first fraction to get 16/20 and repeat on the other side 1*5 and 4*5 or 5/20 so the to fractions are 16/20+5/20 then add just the numerators 16+5=21 or 21/20 and simplify to 1/20

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3 years ago

Which equations are true?

dedylja [7]

Answer:

A and B

Step-by-step explanation:

A) Collect like terms

0=0

B) Collect like terms

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A and B both correct

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2 years ago

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Colossus Added to six flags st. Louis in 1986, the Colossus is a giant Ferris wheel. Its diameter is 165 feet, it rotates at a r

NemiM [27]

Given:

D=165 feet and the frequency of the motion is 1.6 revolutions per minute.

Solution:

The radius is half of the diameter.

The radius of the wheel is 82.5 feet.

$T=\frac{1}{1.6} \text{ minutes}$

As we know: $\omega=\frac{2\pi}{T}$

Substitute the value of T in the above formula.

$\omega=\frac{2\pi}{\frac{1}{1.6}}\\\omega=3.2\pi$

If the center of the wheel is at the origin then for $t=0$ the rest position is $-a$ .

This can be written as:

$h(t)=-a\cos(\omega t)\\h(t)=-82.5cos(32.\pi t)$

The actual height of the rider from the ground is:

$h(t)=\text{ Initial height from bottom}+\text{ radius}-82.5\cos(3.2\pi t)\\h(t)=15+82.5-82.5\cos(3.2\pi t)\\h(t)=97.5-82.5\cos(3.2\pi t)$

The required equation is $h(t)=97.5-82.5\cos(3.2\pi t)$ .

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3 years ago

Need help on math question thanks <br> A) 0.303 <br> B) 0.435 <br> C) 0.406<br> D) 0.154

Airida [17]

Answer:

A) 0.303

The probability that a randomly selected student from the class has brown eyes , given they are male

$P(\frac{B}{M} ) = 0.3030$

Step-by-step explanation:

<u>Explanation</u>:-

Given data

Brown Blue Hazel Green

Females 13 4 6 9

Males 10 2 9 12

<em>Let 'B' be the event of brown eyes </em>

<em>Total number of males n(M) = 33</em>

Let B/M be the event of randomly selected student from the class has brown eyes given they are male

<em>The probability that a randomly selected student from the class has brown eyes , given they are male</em>

<em></em> $P(\frac{B}{M} ) = \frac{n(B)}{n(M)}$ <em></em>

<em>From table the brown eyes from males = 10</em>

$P(\frac{B}{M} ) = \frac{10}{33}$

$P(\frac{B}{M} ) = 0.3030$

<u>Final answer</u>:-

The probability that a randomly selected student from the class has brown eyes , given they are male

$P(\frac{B}{M} ) = 0.3030$

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3 years ago

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d1i1m1o1n [39]

Answer:

B or C hope it helps :)

Step-by-step explanation:

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