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2 years ago

Please help I’ll give brainliest

Mathematics

2 answers:

Minchanka [31]2 years ago

6 0

Answer:

the answer which you have opted is perfect

Daniel [21]2 years ago

6 0

I think that answer is the right one?

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Solve |x| < 13<br> A. {-13, 13}<br> B. {x| -13< x < 13}<br> C. {x|x < -13, x> 13}

Gemiola [76]

Answer:

the solution for x will be given by {x| -13 < x < 13}

Therefore the correct option is B.

Step-by-step explanation:

i) given that |x| < 13

ii) therefore x < 13 for positive values of x

iii) for negative values of x we have -x < 13

therefore x > -13

iv) from ii) and iii) above we can conclude that the solution for x will be given by {x| -13 < x < 13}

Therefore the correct option is B.

7 0

2 years ago

5^(-x)+7=2x+4 This was on plato

Setler79 [48]

Answer:

Below

I hope its not too complicated

$x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}$

Step-by-step explanation:

$5^{\left(-x\right)}+7=2x+4\\\\\mathrm{Prepare}\:5^{\left(-x\right)}+7=2x+4\:\mathrm{for\:Lambert\:form}:\quad 1=\left(2x-3\right)e^{\ln \left(5\right)x}\\\\\mathrm{Rewrite\:the\:equation\:with\:}\\\left(x-\frac{3}{2}\right)\ln \left(5\right)=u\mathrm{\:and\:}x=\frac{u}{\ln \left(5\right)}+\frac{3}{2}\\\\1=\left(2\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)-3\right)e^{\ln \left(5\right)\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)}$

$Simplify\\\\\mathrm{Rewrite}\:1=\frac{2e^{u+\frac{3}{2}\ln \left(5\right)}u}{\ln \left(5\right)}\:\\\\\mathrm{in\:Lambert\:form}:\quad \frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}$

$\mathrm{Solve\:}\:\frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}:\quad u=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)\\\\\mathrm{Substitute\:back}\:u=\left(x-\frac{3}{2}\right)\ln \left(5\right),\:\mathrm{solve\:for}\:x$

$\mathrm{Solve\:}\:\left(x-\frac{3}{2}\right)\ln \left(5\right)=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right):\\\quad x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}$

3 0

3 years ago

HELP FAST FAST FAST PLSS

Ivan

Answer:

B. Distributive Property

Step-by-step explanation:

The distributive property tells us that a(b+c)=(a×b)+(a×c).

Same with the question.

9(16+20)=(9×16)+(9×20).

6 0

3 years ago

Read 2 more answers

Which statement about the equation is true? x + 2 = x + 4

ryzh [129]

No solution because you can’t even out both sides

6 0

3 years ago

Read 2 more answers

Oh yeah by the way its 30 cause i'm big brain

Llana [10]

Answer:

mmk (randon text because why not, but it was the most important part in a lot more time and than I did before I dont think about a new job and a lot of work can happen to get milk and I want a new life

6 0

3 years ago