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2 years ago

A culture started with 5,000 bacteria. After 4

Mathematics

1 answer:

Lisa [10]2 years ago

7 0

Answer:

5000 * (e^((1 /4) * ln(55 / 50) * (13))) = 6,815.47

Step-by-step explanation:

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Find the hypotenuse of a triangle that has an 8 cm width and a height of 12 cm.

anygoal [31]

Answer:14

Step-by-step explanation:

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2 years ago

Classify the following triangle. Check all that apply.60"30A. scaleneB. isoscelesC, equilateralD, rightE. obtuseF. acute

borishaifa [10]

That's a scalene right triangle.

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2 years ago

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A type of restaurant menu that has all components of a meal (meat, starch, vegetable) priced

kifflom [539]

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A. fixed

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2 years ago

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1=10^0 into logarithmic form

Tatiana [17]

Answer:

$0 = log_{10} 1$

Step-by-step explanation:

Base for the exponent and for the logarithm are the same!

10^0 is the <u>exponential</u> form where 10 is the base and 0 the exponent

$log_{10} 1$ is the l<u>ogarithm</u> form where 10 is the base

To solve $log_{10} 1 =$ ask the question :

To what power should I raise the base 10 to obtain the number 1 ?

The answer to the power 0 therefore

$log_{10} 1 = 0$

$1 = 10^{0} -is-the- exponential -form\\0 = log_{10} 1 - is -the -logarithmic -form$

7 0

1 year ago

the figure below shows a circle centre of radius 10 cm the chord PQ=16cm calculate the area of the shaded region

m_a_m_a [10]

Step-by-step explanation:

OPQ originally forms a sector, the formula for sector is

$\frac{x}{360} \pi {r}^{2}$

where x is the degrees of rotation between the two radii.

We know three sides length and is trying to find an angle between the radii so we can use law of cosines which states that

$16 = \sqrt{10 {}^{2} + 10 {}^{2} - 2(100) \times \cos(o) }$

This isn't the standard formula, it's for this problem

$16 = \sqrt{200 - 200 \times \cos(o) }$

$16 = \sqrt{200 - 200 \cos(o) }$

$256 = 200 - 200 \cos(o)$

$56 = - 200 \cos(o)$

$- \frac{7}{25} = \cos(o)$

$\cos {}^{ - 1} ( - \frac{7}{25} ) = \cos {}^{ - 1} ( \cos(o) )$

$106.26 = o$

So we found our angle of rotation, which is 106.26

Now, we do the sector formula.

$\frac{106.26}{360} (100)\pi$

$\frac{10626}{360} \pi$

is the area of sector.

Now let find the area of triangle, we can use Heron formula,

The area of a triangle is

$\sqrt{s(s - a)(s - b)(s - c)}$

where s is the semi-perimeter.

To find s, add all the side lengths up, 10,10,16 and divide it by 2.

Which is

$\frac{36}{2} = 18$

$\sqrt{18(18 - 10)(18 - 10)(18 - 16)}$

$\sqrt{18(8)(8)(2)}$

$\sqrt{(36)(64)}$

$6 \times 8 = 48$

So our area of the triangle is 48. Now, to find the shaded area subtract the main area,( the sector of the circle) by the area of the triangle so we get

$\frac{10626}{360} - 48$

Which is an approximate or

44.73

6 0

1 year ago