Step-by-step explanation:
0.89 = 1 - 1/(k²)
Start by subtracting 1 from both sides:
0.89 - 1 = -1/(k²)
-0.11 = -1/(k²)
Multiply both sides by -1:
0.11 = 1/(k²)
Multiply both sides by k²:
0.11 k² = 1
Divide both sides by 0.11:
k² = 1 / 0.11
Take the square root:
k = √(1 / 0.11)
<h2>In triangle BDE and triangle BAC</h2><h2>Angle B = Angle B (Common) </h2><h2>Angle BDE = Angle BAC </h2><h2>Therefore, triangle BDE is congruent to triangle BAC (AA similarity) </h2><h2>Hence proved. </h2>
Hope it helps :)
Answer:
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Step-by-step explanation:
Let 11x + 15y + 23 = 0 be equation (1)
And 7x - 2y - 20 = 0 be equation (2)
Multiply equation (1) by 2:
22x + 30y + 46 = 0
Multiply equation (2) by 15:
105x - 30y - 300 = 0
Add equations (1) and (2):
22x + 105x + 30y - 30y + 46 - 300 = 0
127x - 254 = 0
127x = 254
x = 254/127
[x = 2]
Substitute x = 2 in equation (1) to find y:
11(2) + 15y + 23 = 0
22 + 15y + 23 = 0
15y + 45 = 0
15y = -45
y = -45/15
y = -3
Therefore, x = 2 and y = -3.