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lozanna [386]
2 years ago
8

7/7q+21= x /5q^2-45 then x=?​

Mathematics
1 answer:
anzhelika [568]2 years ago
3 0

Answer:

x = 5q - 15

Step-by-step explanation:

\frac{7}{7q+21}=\frac{x}{5q^{2}-45}\\\\\frac{7}{7(q+3)}=\frac{x}{5 (q^{2} -9)}\\\\frac{1}{q+3}=\frac{x}{5*(q^{2}-3^{2})}\\\\\frac{1}{q+3}=\frac{x}{5(q+3)(q-3)}\\\\\frac{1}{q+3}*5*(q+3)(q-3)=x\\\\5(q-3)=x\\\\x= 5q-15

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\bf \begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&U&(~ a &,& 0~) &#10;%  (c,d)&#10;&V&(~ x &,& y~)&#10;\end{array}&#10;\\\\\\&#10;% slope  = m&#10;slope =  m\implies &#10;\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{y-0}{x-a}~~=~~\stackrel{ZW's~slope}{\cfrac{b}{-a}}&#10;\\\\\\&#10;\begin{cases}&#10;y-0=b\implies \boxed{y=b}\\&#10;-----------\\&#10;x-a=-a\implies \boxed{x=0}&#10;\end{cases}\qquad \qquad V~(0,b)

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