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3 years ago

7/7q+21= x /5q^2-45 then x=?

Mathematics

1 answer:

anzhelika [568]3 years ago

3 0

Answer:

x = 5q - 15

Step-by-step explanation:

$\frac{7}{7q+21}=\frac{x}{5q^{2}-45}\\\\\frac{7}{7(q+3)}=\frac{x}{5 (q^{2} -9)}\\\\frac{1}{q+3}=\frac{x}{5*(q^{2}-3^{2})}\\\\\frac{1}{q+3}=\frac{x}{5(q+3)(q-3)}\\\\\frac{1}{q+3}*5*(q+3)(q-3)=x\\\\5(q-3)=x\\\\x= 5q-15$

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7/7q+21= x /5q^2-45 then x=?​

7/7q+21= x /5q^2-45 then x=?