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3 years ago

Identify the two missing sides of the 45-45-90 triangle

Mathematics

1 answer:

Naily [24]3 years ago

4 0

X= 8

y= 8root2

........................

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Place pi squared, 10, and square root of 70 in least to greatest

Nutka1998 [239]

Answer:

squaare root of 70<pi squared<10

Step-by-step explanation:

Talking about square root of 70, you can take the answer by approximation. u know square of eight is sixty four and square of nine is eighty one. so 70's square root shluld be between eight and nine. And as the value of pi is 3.14... when square of pi is considerd it should be >9 but <10 as pi>3. So 10 become te greatest

3 0

3 years ago

Find the Surface Area of the prism pleese

Alina [70]

Answer:

I'm unsure of the answer but here's how to solve it yourself :)

Step-by-step explanation:

area of a prism is obtained by taking the sum of (twice the base area) and (the lateral surface area of the prism). The surface area of a prism is given as S = (2 × Base Area) + (Base perimeter × height) where "S" is the surface area of the prism.

5 0

2 years ago

Factor 18s-63 A 9(2s+7) B 6(3s-11) C 18(s-3) D 9(2s-7)

Lunna [17]

Answer:

it's D

Step-by-step explanation:

pls give me da crown

6 0

3 years ago

A pet supply chain called Pet City has 5 hamsters and 10 gerbils for sale at its Lanberry location. At its Milford location, the

Vlad1618 [11]

Answer:

Milford location has a higher ratio of hamsters to gerbils.

Step-by-step explanation:

Given:

A pet supply chain called Pet City has 5 hamsters and 10 gerbils for sale at its Lanberry location.

At its Milford location, there are 13 hamsters and 16 gerbils.

Now, to find the location who has a higher ratio of hamsters to gerbils.

Ratio of hamsters to gerbils at Lanberry location = 5:10.

$=\frac{5}{10}=0.50$

Ratio of hamsters to gerbils at Milford location= 13:16.

$=\frac{13}{16} =0.8125$

So, 0.8125 > 0.50.

Thus, 13:16 > 5:10.

Therefore, Milford location has a higher ratio of hamsters to gerbils.

4 0

3 years ago

Hi i just need help checking if my answer is correct I have been working on a implicit diffrention problem and I need some help.

SSSSS [86.1K]

Answer:

$\dfrac{dy}{dx}=\dfrac{-4x^3y+2y^3+3x^2y^3}{x^4-6xy^2-3x^3y^2}$

Step-by-step explanation:

Normally, when I do this, I differentiate each term first with respect to x then with respect to y. In this solution, I differentiated the entire expression with respect to x, then with respect to y. That makes separating the dx and dy coefficients much easier, so the solution almost falls into your lap.

$-x^4 y + 2 x y^3 + x^3 y^3=0 \qquad\text{given}\\\\(-4x^3y+2y^3+3x^2y^3)dx+(-x^4+6xy^2+3x^3y^2)dy=0\\\\(-4x^3y+2y^3+3x^2y^3)dx=(x^4-6xy^2-3x^3y^2)dy\\\\\boxed{\dfrac{dy}{dx}=\dfrac{-4x^3y+2y^3+3x^2y^3}{x^4-6xy^2-3x^3y^2}}$

6 0

3 years ago