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Semenov [28]
2 years ago
8

Give a numerical example to represent this rule.

Mathematics
1 answer:
RideAnS [48]2 years ago
5 0

A non-negative number is a number which is either zero or a positive number

For numerical example , to satisfy rule \sqrt[k]{a^{m} } =(\sqrt[k]{a} )^{m} substitute a = 16, m = 2 and k = 2

The square root of a number is the number that we need to multiply by itself to get the original number

Now substituting, a = 16, m = 2 and k = 2 in given rule

            \sqrt[2]{16^{2} } =(\sqrt[2]{16} )^{2} \\\\\sqrt[2]{16*16}=\sqrt[2]{16}*  \sqrt[2]{16}\\\\16=16

So,  \sqrt[2]{16^{2} } satisfy the given rule.

Learn more;

brainly.com/question/13277609

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(-2,3)(0,8) what is en equation for these points
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Answer:

The line equation that passes through the given points is          5x – 2y + 16 = 0

Explanation:

Given:

Two points are A(-2, 3) and B(0, 8).

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The line equation that passes through the given two points.

Solution:

We know that, general equation of a line passing through two points (x1, y1), (x2, y2) is given by

\frac{(y- y1)}{(x-x_1)}= \frac{((y_2- y_1)}{(x_2- x_1 )}

{(y- y1)= \frac{((y_2- y_1)}{(x_2- x_1 )}\times(x-x_1).............(1)

here, in our problem x1 = 0, y1 = 8, x2 = -2 and y2 = 3.

Now substitute the values in (1)

y-8 = \frac{(3-8)}{(- 2 - 0)}\times(x- 0)

y-8 = \frac{(- 5)}{(-2)}\times(x)

y-8 =\frac{5}{2}x

2y – 16 = 5x

5x – 2y + 16 = 0

Hence, the line equation that passes through the given points is 5x – 2y + 16 = 0.

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