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2 years ago

PLEASE HELP WILL MARK BRAINLIEST TO BEST ANSWER

Mathematics

2 answers:

marysya [2.9K]2 years ago

7 0

Answer:I would say A I found out 2X^2+-1 first

Step-by-step explanation:2x

+−1

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax

is nax

n−1

2×2x

2−1

Multiply 2 times 2.

2−1

Subtract 1 from 2.

For any term t, t

=t.

Then I saw that 6-2 making 4 so I chose the first one

sergeinik [125]2 years ago

6 0

Answer:

option D

${10x}^{2} + 3x - 8$

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If x = 4y + 21y and y = 14 + 5, what is 3x × 7? No need to show your work.

podryga [215]

y = 19

x = 4(19) + 21(19) = 76 + 399 = 475

3(475) × 7

1425 × 7

9975 <--- answer.

Hope this helped!

Nate

7 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP!!!!!!

lorasvet [3.4K]

I'm not sure what the question is but it looks like it's B

5 0

2 years ago

Can you please help me

Mandarinka [93]

Answer: Attached.

Step-by-step explanation:

Either solve the equations directly, or graph them and look for the point of intersection.

8 0

2 years ago

The perimeter of equilateral triangle ABC is 81/3 centimeters, find the length of the radius and apothem.

MAXImum [283]

There is a typo error, the perimeter of equilateral triangle ABC is 81/√3 centimeters.

Answer:

Radius = OB= 27 cm

Apothem = 13.5 cm

A diagram is attached for reference.

Step-by-step explanation:

Given,

The perimeter of equilateral triangle ABC is 81/√3 centimeters.

Substituting this in the formula of perimeter of equilateral triangle = $3\times\ side$

$3\times\ side$ $=[tex]81\sqrt{3}$

$Side = \frac{81\sqrt{3} }{3} =27\sqrt{3} \ cm$

Thus from the diagram , Side $AB=BC=AC= 27\sqrt{3} \ cm$

We know each angle of an equilateral triangle is 60°.

From the diagram, OB is an angle bisector.

Thus $\angle OBC = 30$ °

Apothem is the line segment from the mid point of any side to the center the equilateral triangle.

Therefore considering ΔOBE, and applying tan function.

$tan\theta =\frac{perpendicular}{base} \\tan\theta=\frac{OE}{BE} \\tan\theta=\frac{OE}{\frac{27\sqrt{3}}{2} } \\tan30\times {\frac{27\sqrt{3} }{2} }= OE\\\frac{1}{\sqrt{3} } \times\frac{27\sqrt{3} }{2} =OE\\$

Thus ,apothem OE= 13.5 cm

Now for radius,

We consider ΔOBE

$cos\theta=\frac{base}{hypotenuse} \\cos30= \frac{BE}{OB} \\Cos30 = \frac{\frac{27\sqrt{3} }{2}}{OB} \\OB= \frac{\frac{27\sqrt{3} }{2}}{cos30} \\OB= \frac{\frac{27\sqrt{3} }{2}}{\frac{\sqrt{3} }{2} } \\OB =27 \ cm$

Thus for

Perimeter of equilateral triangle ABC is 81/√3 centimeters,

The radius of equilateral triangle ABC is 27 cm

The apothem of equilateral triangle ABC is 13.5 cm

4 0

2 years ago

What is the equation of the line that passes through the points (2, –1) and (6, 1)?

Zolol [24]

Y=kx+b
2k+b=-1
6k+b=1
6k+b-2k-b=2
4k=2
k=1/2
b=-2
y=1/2x-2
So your answer is option A

8 0

2 years ago